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rusak2 [61]
3 years ago
11

Hi, can somebody help me, I can't figure out how to get the surface area of a rectangular prism: height is 2, width is 4 and len

gth is 4.5
thank you
Mathematics
1 answer:
masya89 [10]3 years ago
8 0
All u have to do is width times height and length the area is 36
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A software company is releasing one of their products on a CD. The manufacturer charges a $9700 setup fee and $1.25 per CD. Appr
Gre4nikov [31]

Answer:

  about 4312

Step-by-step explanation:

You want the total cost for n CDs to be 3.50n.

The manufacturer will charge you 9700+1.25n, so you want these to be equal:

  3.50n = 9700 +1.25n

  2.25n = 9700 . . . . . . . . subtract 1.25n

  n = 9700/2.25 ≈ 4311.111...

Producing 4312 CDs will make the cost per CD slightly less than $3.50.

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Producing 4311 CDs will make the cost per CD be about $3.500058. Producing 4312 CDs will bring it down to $3.499536.

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3 years ago
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That would be... 936.12
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2 years ago
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A rectangular prism and a triangular prism each have a volume of 210 cubic meters. find possible dimensions for each prism.
Evgesh-ka [11]
An interesting question! Let's take a look at the rectangular prism first.

[Rectangular Prism]
We know that the formula for the volume of a rectangular prism is:
volume = length * width * height

or more simply
V = L*W*H

All we know is that the volume is 210 cubic meters. We can choose whatever we want for the dimensions to force it to work! We're free to do what we want!
210 = L*W*H

I like 10, that's a nice number. Let's make L = 10.
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Hmm... but now I need W*H to be 21 (think about it, make sure you get why I say that). Well, how about W = 7 and H = 3? That should work.
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It checks! Possible dimensions for the rectangular prism are L = 10 meters, W = 7 meters, and H = 3 meters. There are many other choices of course, but this is a possible choice.

[Triangular Prism]
Same idea, different formula. For a triangular prism, the volume is
V = 1/2 * L*W*H

But the volume is still 210 cubic meters, so we just have
210 = 1/2 * L*W*H

So, one of our dimensions is going to be cut in half. Why don't we just double L to make up for it? 
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And we can leave W and H the same
210 = 1/2*20*7*3

Check that it works! A possible choice is L = 20 meters, W = 7 meters and H = 3 meters.

We're done!

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3 years ago
Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit
Virty [35]
Hence it is a simply rearrangement of the equation to start with, in order to make  the subject:






This is the graph in 'slope-intercept' form. From here it is easy to see that gradient  = and that y-intercept = 490.

The easiest way to draw a straight-line graph, such as this one, is to plot the y-intercept, in this case (0, 490), then plot another point either side of it at a fair distance (for example substitute  = -5 and  = 5 to procure two more sets of co-ordinates). These can be joined up with a straight line to form a section of the graph, which would otherwise extend infinitely either side - use the specified range in the question for x-values, and do not exceed it (clearly here the limit of -values is 0 ≤ x ≤ 735, since neither x nor y can be negative within the context of the question - the upper limit was found by substituting  = 0).

In function notation, the graph is:



The graph of this function represents how the value of the function varies as the value of x varies. Looking back at the question context, this graph specifically represents how many wraps could have been sold at each number of sandwich sales, in order to maintain the same profit of $1470.

When the profit is higher, the gradient is not changed (this is defined by the relationship between the $2 and $3 prices, not the overall profit) - instead the -intercept is higher:






Therefore we have gleaned that the new y-intercept is.

Clearly I cannot see the third straight line. However the method for finding the equation of a straight line graph is fairly simple:

1. Select two points on the line and write down their coordinates
2. The gradient of the line = 
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4. Find the change in  (Δ
5. Divide the result of stage 3 by the result of stage 4
6. This is your gradient
7. Take one of your sets of coordinates, and arrange them in the form , where your  is the gradient you just calculated
8. There is only one variable left, which is  (the y-intercept). Simply solve for this
9. Now generalise the equation, in the form , by inputting your gradient and y-intercept whilst leaving the coordinates as  and 

For example if the two points were (1, 9) and (4, 6):

Δ = 6 - 9 = -3
Δ = 4 - 1 = 3
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I choose the point (4, 6)
6 = (-1 * 4) + c
6 = c - 4
c = 10
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3 years ago
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Gala2k [10]

Answer:

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I think this is correct

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