PLEASE HELP, THIS ONE IS EVEN MORE CONFUSING THAN THE OTHER ONE I ASKED xDDD

Serena is the manager at the coffee shop .the amount of money she earns is represented by the equation m= 21h , where h is the a

shutvik [7]

21 - 13.50= 7.50

so based on what your question is asking, Serena makes $7.50 more than Gabe per hour.

8 0

3 years ago

Read 2 more answers

A rancher has 200 feet of fencing to enclose two adjacent corrals

Arturiano [62]

Answer:

a) Each corral should be 33⅓ ft long and 25 ft wide

b) The total enclosed area is 1666⅔ ft²

Step-by-step explanation:

I assume that the corrals have identical dimensions and are to be fenced as in the diagram below

Let x = one dimension of a corral

and y = the other dimension

(a) Dimensions to maximize the area

The total length of fencing used is:

4x + 3y = 200

4x = 200 – 3y

x = 50 - ¾y

The area of one corral is A = xy, so the area of the two corrals is

A = 2xy

Substitute the value of x

A = 2(50 - ¾y)y

A = 100 y – (³/₂)y²

This is the equation for a downward-pointing parabola:

A = (-³/₂)y² + 100y

a = -³/₂; b = 100; c = 0

The vertex (maximum) occurs at

y = -b/(2a) = 100 ÷ (2×³/₂) = 100 ÷ 3 = 33⅓ ft

4x + 3y = 100

Substitute the value of y

4x + 3(33⅓) = 200

4x + 100 = 200

4x = 100

x = 25 ft

Each corral should measure 33⅓ ft long and 25 ft wide.

Step 2. Calculate the total enclosed area

The enclosed area is 50 ft long and 33⅓ ft wide.

A = lw = 50 × 100/3 = 5000/3 = 1666⅔ ft²

6 0

2 years ago

In triangle ACE, P is the centroid, PF = 6 , and AD = 15 15. Find the measures of PC and AP. Enter your answers as numbers.

xxTIMURxx [149]

Answer:

PC = 12 units

AP = 10 units

Step-by-step explanation:

The centroid of a triangle is the intersection of the three medians of the triangle

Each median connecting a vertex with the midpoint of the opposite side

The centroid divides each median into two parts, which are always in the ratio 2: 1 from the vertex

In ΔACE

∵ P is the centroid of it

∴ P divides CF the ratio 2: 1 from C

∴ PC = 2 PF

∵ PF = 6 units

∴ PC = 2(6)

∴ PC = 12 units

∵ P divides AD at the ratio 2: 1 from A

→ That means AD = 2 + 1 = 3 parts, and AP = $\frac{2}{3}$ AD

∴ AP = $\frac{2}{3}$ AD

∵ AD = 15 units

∴ AP = AP = $\frac{2}{3}$ (15)

∴ AP = 10 units

5 0

2 years ago

Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1

elena-s [515]

Answer:

a) $P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

b) $P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

c) $0.75 =\frac{0.83}{1+e^{-0.2n}}$

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

d) If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

$P(n) = \frac{0.83}{1+e^{-0.2t}}$

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

$P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

So the number of correct reponses after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

$P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

$0.75 =\frac{0.83}{1+e^{-0.2n}}$

And we can rewrite this expression like this:

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

Now we can apply natural log on both sides and we got:

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

5 0

2 years ago

How to compare 2 5/9 and 21/3

max2010maxim [7]

Answer:

2 5/9 is less than 21/3; 2 5/9 < 21/3

Step-by-step explanation:

Step 1: Convert 2 5/9 into an improper fraction

2 5/9 = 2 * 9/9 + 5/9 = 18/9 + 5/9 = 23/9

Step 2: Convert 21/3 so the denominator is 9

21*3 / 3*3 = 63/9

Step 3: Compare

23/9 < 63/9

Answer: 2 5/9 is less than 21/3; 2 5/9 < 21/3

5 0

2 years ago

Read 2 more answers