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Afina-wow [57]
3 years ago
6

Pls help , giving brainliest

Mathematics
2 answers:
11111nata11111 [884]3 years ago
8 0

Answer:

(-5),-2)=-7

(-5,-6)=-11

is 77 all

suter [353]3 years ago
6 0

Step-by-step explanation:

Distance between points =>

d =  \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2}  }  \\  \\  =  \sqrt{( - 5 +5) {}^{2}  +(  - 6 + 2) {}^{2} }  \\  \\  =  \sqrt{0 - 16 }  \\  \\  =  \sqrt{-16 }  \\  \\  = 4i

The distance is 4i units.

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Help!!! This question is confusing me!!
erica [24]

Answer:

k ≥2

Step-by-step explanation:

k+ 1/3≥7/3

Subtract 1/3 from each side

k+ 1/3-1/3≥7/3-1/3

k ≥6/3

k ≥2

8 0
4 years ago
A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
4 years ago
The difference of the degrees of the polynomials p(x) = 3x2y2 + 5xy? - x6 and q(x) = 3x5 - 4x3 + 2 is
svet-max [94.6K]

Answer:

The difference of the degrees of the polynomials p (x) and q (x) is 1.

Step-by-step explanation:

A polynomial function is made up of two or more algebraic terms, such as p (x), p (x, y) or p (x, y, z) and so on.

The polynomial’s degree is the highest exponent or power of the variable in the polynomial function.

The polynomials provided are:

p(x) = 3x^{2}y^{2} + 5xy - x^{6}\\\\q(x) = 3x^{5} - 4x^{3} + 2

The degree of polynomial p (x) is:

\text{deg}\ p (x)=6

The degree of polynomial q (x) is:

\text{deg}\ q (x)=5

The difference of the degrees of the polynomials p (x) and q (x) is:

\text{deg}\ p(x)-\text{deg}\ q(x)=6-5=1

Thus, the difference of the degrees of the polynomials p (x) and q (x) is 1.

6 0
4 years ago
-x^2+4x-8 <br>axis of symmerty​
V125BC [204]

Answer:

\boxed {\boxed {\sf x=2}}

Step-by-step explanation:

The axis of symmetry can be calculated using the formula:

x=\frac{-b}{2a}

First we must determine a and b from the quadratic: -x^2+4x-8. This is in standard form, with the highest power first in descending order.

Standard form is also: ax^2+bx+c

If we compare this to the quadratic given, we can conclude that:

a= -1 \\b= 4 \\c= -8

Substitute the values for a and b into the formula.

x= \frac{-(4)}{2(-1)}

Multiply in the denominator.

x=\frac {-4}{-2}

Divide.

x=2

This can also be determined from the graph. It is the x-coordinate of the vertex or the maximum/minimum. It divides the quadratic into 2 symmetrical halves.

8 0
3 years ago
 An athlete runs an equal distance 2 days a week. The other 5 days of the​ week, he runs a total of 11 miles. Write an equation
katovenus [111]
Ok since the athlete an equal distance of 2 days a week and he runs a total of 11 miles in 5 days you will need to think back so before he had 11 miles done next weak he had a total of 19 miles so you will start at 11 then count up to 19.

Use a number line to show how many days it took for the athlete to get 19 miles.

Then once you do the number line count the lumps and that’s how many days it took for the athlete to get 19 miles.

Hope this helped.
3 0
3 years ago
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