Question

Smedly has just drawn two rectangles. The length of the first rectangle is 4 cm more than the length of the second. The width of the first is 9 cml the width of the second is 6 cm. If the area of the first rectangle is 96cm

Answer 1

Answer:

The area of the second rectangle is $A=42cm^{2}$

Step-by-step explanation:

Please see the picture below.

Let´s name the length of the second rectangle as x, so the length of the first rectangle will be 4+x.

The formula of the area of the rectangle is given by

$A=length*width$

Replacing values:

$96cm^{2}=(4cm+x)*9cm$

$96cm^{2}=36cm+9cm*x$

Solving for x:

$96cm^{2}-36cm=9cm*x$

$60cm=9cm*x$

$x=\frac{60cm}{9cm}$

$x=7cm$

Find the area of the second rectangle:

$A=length*width$

$A=x*6cm$

$A=7cm*6cm$

$A=42cm^{2}$