When the object reaches the ground, the height is zero, so:
0 = 144 - 16t^2
then you just solve for t, so subtract the 144 over
-144 = -16t^2
then divide by the -16
9 = t^2
then take the square root of both sides
3 = t
therefore, it will take three seconds for the object to reach the ground.
Hello!
For this you can substitute one of the y's with the other equation
-2x + 2 = -2x - 2
Add 2x to both sides
2 = 0x - 2
Add 4 to both sides
4 = 0
Since 4 does not equal 0 the answer is No solution
Hope this helps!
Answer:
Duh $6
Step-by-step explanation:
its simple math
Answer:
x= 20 and y=140
all the steps are on the image :)
-2-(-6) = 4. Put the plotting dot on 4 :)