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almond37 [142]
3 years ago
15

How do horizontally organized companies differ from traditionally organized companies

Business
1 answer:
GenaCL600 [577]3 years ago
7 0

Horizontally organised companies do not have a strict hierarchy of posts with increasing importance and allow more freedom to the employees.

Explanation:

Horizontally organised companies function very differently from traditional companies as the traditional structure is a pyramidal vertical structure.

<u>In this structure people at the top are few and are at higher  positions and issue orders which are distributed by managers to employees.</u>

<u>In the horizontal structure the managers are taken out of play and even the employees make important decisions for the company.</u> This allows for greater morale and freedom but can only work for small and medium sized businesses in certain niches.

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Trade restrictions tend to preserve relatively few jobs in the protected industries and lead to job losses in other industries. Trade restrictions can vary from quotas, embargoes, standards, subsidies, tariffs and more that make it hard to trade (important/export) goods between two companies and also set prices for these. Depending on what is allowed and what is not different industries can benefit from the trade restrictions and some can be harmed by them. 
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A major conflict of interest between top executives and owners, is that top executives wish to diversify the firm in order to ,
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Net income increases when: Group of answer choices fixed costs increase. depreciation increases. the average tax rate increases.
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Net income increases when "revenue" increases.

<h3>What is revenue?</h3>

The overall revenue generated by a business over a predetermined period of time. This can be done by-

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3 years ago
The demand for a new computer game can be modeled by p (x )equals 48.5 minus 5 ln x​, for 0less than or equalsxless than or equa
Hoochie [10]

Answer:

a. R(x) = 48.5x - x5inx

b. R'(x) = 43.5 - 5lnx

c. The correct option is d. Yes, because the revenue will be maximized when R'(x)=0. The price to the consumer would be <u>$5</u>.

Explanation:

Given:

p(x) = 48.5 - 5lnx, for 0 ≤ x ≤ 800 ............. (1)

a. Find R(x).

R (x) = x * p (x) ........................ (2)

Substitute equation (1) into (2), we have:

R(x) = x(48.5 - 5lnx)

R(x) = 48.5x - x5inx .............................. (3)

Equation (1) is the R(x) required to be found.

b. Find the marginal revenue, R'(x)

The derivative of equation (3) is taken to obtain R'(x) as follows:

R'(x) = 48.5 - 5lnx - x5(1/x)

R'(x) = 48.5 - 5lnx - 5

R'(x) = 48.5 - 5 - 5lnx

R'(x) = 43.5 - 5lnx ...................... (4)

Equation (4) is the marginal revenue, R'(x), required to found.

c. Is there any price at which revenue will be maximized? Why or why not? Choose the correct answer below.

Profit is maximized when R'(x) = 0

Equating equation (4) to 0 and solve for x, we have:

43.5 - 5lnx = 0

43.5 = 5lnx

5lnx = 43.5

lnx = 43.5 / 5

x = e^(43.5 / 5)

x = 6,002.91

Substituting x = 6,002.91 into equation (1), we have:

p(x) = 48.5 - (5 * ln(6,002.91))

p(x) = 48.5 - (5 * 8.70)

p(x) = 48.5 - 43.5

p(x) = $5

Therefore, the correct option is d. Yes, because the revenue will be maximized when R'(x)=0. The price to the consumer would be <u>$5</u>.

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