Answer:
Step-by-step explanation:
For species A,

For species B,

When their populations are equal,

The diagram below shows the population of Species A overtaking that of Species B in about 30.5 yr.
Answer:
Step-by-step explanation: how many frenis are there?
You have a lot of questions here, I can help you with a few of them.
When you simplify the polynomials, you put together all of the terms that have the same degree. That means the variables have the same exponents. The number of terms are the items separated by plus and minus signs.
Here are the answers for the first three:
1)

2)

3)
The answer would be C. to find this use the rise over run method