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3 years ago

A soccer ball kicked from the ground with an initial velocity of 32 ft/s is given by the function

Mathematics

2 answers:

Greeley [361]3 years ago

6 0

Answer:

In words the answer is between t=0 and t=2.

In interval notation the answer is (0,2)

In inequality notation the answer is 0<t<2

Big note: You should make sure the function I use what you meant.

Step-by-step explanation:

I hope the function is h(t)=-16t^2+32t because that is how I'm going to interpret it.

So if we can find when the ball is on the ground or has hit the ground (this is when h=0) then we can find when it is in the air which is between those 2 numbers.

0=-16t^2+32t

0=-16t(t-2)

So at t=0 and t=2

So the ball is in the air between t=0 and t=2

Interval notation (0,2)

Inequality notation 0<t<2

Scorpion4ik [409]3 years ago

5 0

Answer:

Its C on edg

Step-by-step explanation:

follow my ifunny "dankmemehistory"

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When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive

For example:

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1. $\frac{10^{15}}{10^3} =10^{15-3} = 10^{12}$

2. $\frac{(-3)^4}{(-3)^{-3}} =(-3)^{4-(-3)}=(-3)^{4+3} = (-3)^7$

3. $\frac{8}{8^3} =8^{1-3} = 8^{-2}=\frac{1}{8^2}$

4. $\frac{a^{12}}{a^2} =a^{12-2}=a^{10}$

5. $\frac{m^{-2}n^{16}}{m^{4}n^2} =(m^{-2-4})(n^{16-2})=(m^{-6})(n^{14})=\frac{n^{14}}{m^{6}}$

This is one of the ways you could have done it

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[More information with exponents]

If you multiply an exponent directly with another exponent, you multiply the exponents together

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$(x^{2})^4=x^{2(4)}=x^8$

$(x^{3})^5 =x^{3(5)}=x^{15}$

If you multiply a variable with an exponent by a variable with an exponent, you add the exponents

For example:

$(x^{2}) (x^6)=x^{2+6}=x^8$

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3 years ago

What is the hcf of 60 and 72

umka2103 [35]

Step-by-step explanation:

The highest common factor is found by multiplying all the factors which appear in both lists: So the HCF of 60 and 72 is 2 × 2 × 3 which is 12.

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3 years ago

Read 2 more answers