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Paraphin [41]
3 years ago
7

Is domanin x or y???????????????????????????????????

Mathematics
2 answers:
kompoz [17]3 years ago
8 0

Answer:

The domain is x and the Range is y

Mandarinka [93]3 years ago
6 0

Answer:

x-axis

Step-by-step explanation:

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Hour how much does davon charge per hour for a skateboard rental HELPP I BEG
Setler79 [48]

Answer:

$7

Davon charges $7 per hour of rental

6 0
3 years ago
I need help with 5 thanks
Mars2501 [29]

For every 3 cups of peanuts there are 2 cups of chocolate

9/3 = 3 so 3*2 = 6

For 9 cups of peanuts there are 6 cups of choclate

3 0
3 years ago
Round your answer to the nearest tenth if necessary. Use 3.14 for it.
aliina [53]

Answer:

volume = 10,082.5 in³

Step-by-step explanation:

radius = 26/2 = 13

volume = πr²L = (3.14)(13²)(19) = 10,082.54 in³

6 0
3 years ago
A pet store sells goldfish and hermit crabs,
Elis [28]

Answer:

Cost = \$28

Step-by-step explanation:

Given

Represent Goldfish with g and hermit crabs with h.

The first statement, we have:

7g + 3h = 26

The second statement, we have:

4g + 5h = 28

Required

Determine the selling price of 6 goldfish and 4 hermit crabs

The equations are:

7g + 3h = 26 --- (1)

4g + 5h = 28 --- (2)

Make g the subject in (2)

4g + 5h = 28

4g = 28 - 5h

Divide both sides by 4

g = \frac{1}{4}(28 - 5h)

Substitute \frac{1}{4}(28 - 5h) for g in (1)

7g + 3h = 26

7(\frac{1}{4}(28 - 5h)) + 3h = 26

\frac{7}{4}(28 - 5h) + 3h = 26

Multiply through by 4

4 * \frac{7}{4}(28 - 5h) + 4*3h = 26*4

7(28 - 5h) + 4*3h = 26*4

Open bracket

196 - 35h + 12h = 104

196 -23h = 104

Collect Like Terms

-23h = 104-196

-23h = -92

Make h the subject

h = \frac{-92}{-23}

h = \frac{92}{23}

h = 4

Substitute 4 for h in g = \frac{1}{4}(28 - 5h)

g = \frac{1}{4}(28 - 5*4)

g = \frac{1}{4}(28 - 20)

g = \frac{1}{4}(8)

g = 2

This implies that:

1 goldfish = $2

1 hermit crab = $4

The cost of 6 goldfish and 4 hermit crabs is:

Cost = 6g + 4h

Cost = 6*\$2 + 4*\$4

Cost = \$12 + \$16

Cost = \$28

5 0
3 years ago
calculate the total potential energy in kj of an object whose mass is 20 kg when it is located 20 m below a datum level in a loc
Airida [17]

Answer:

The energy in object is 3.8 Kilo Joules.  

Step-by-step explanation:

We are given the following in the question:

Mass = 20 kg

Height,h = 20 m

g=9.5 m/s^2

Formula:

Potential energy  =

E = Mgh

Putting value we get,

E = 20(20)(9.5)\\E = 3800~J\\E = 3.8~KJ

Thus, the energy in object is 3.8 Kilo Joules.

5 0
3 years ago
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