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raketka [301]
3 years ago
8

1 cup = ___1/2 cups 1 cup= ___ 1/4 cups 1 cup= ___ 1/3 cups

Mathematics
1 answer:
Vesnalui [34]3 years ago
4 0

:

1 cup = 2 1/2 cups 2 1/2 cups make 1 cup and same for others

1 cup = 4 1/4 cups

1 cup = 3 1/3 cups

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A book has a front and a back and 400 pages. The front and back cover are each 0.9mm thick measured to 1 decimal place. Each pag
zhuklara [117]

The minimum thickness of the book would simply be the sum of the thickness of the two cover pages and all the pages in between. That is:

minimum thickness = 0.9 mm * 2 + 0.13 mm * 400

<span>minimum thickness = 53.8 mm</span>

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What is f(-3) if f(x) = 12x + 1] + 5?<br><br> Α. 0<br><br> B. 10<br><br> C. 12<br><br> D. -10
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3 years ago
Please, for me? I need to pass my math class.
Ede4ka [16]

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5 0
3 years ago
A backyard pool has a concrete walkway around it that is 3 feet wide on all sides. The total area of the pool and the walkway is
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Answer:

<h2><em>29.4 length and 21.4 width.</em></h2>

Step-by-step explanation:

To fin the dimensions of the pool we need to use the total area of the pool plus the concrete walkway. Lets say that <em>W </em>is the width and <em>L </em>the length. We know that, the walkway has 3 ft wide, this means that the width and length are increased by 6ft (3ft on each side). So, the total area can be expressed like this:  A_{total} = (L+6)(W+6).

In addition, we know that the total area is 970 and the length is 8 ft longer than the width (L=W+8). So:

A_{total} = (L+6)(W+6)\\970 = (W+8+6)(W+6)\\970=W^{2}+20W+84\\W^{2}+20W-886=0

With this quadratic equation we're gonna have to solution, the most reasonable is part of the answer. So, solving the equation we have as solutions: W_{1}=21.4 and  W_{2}=-41.4

Therefore, the width is 21.4 ft, because the negative number cannot represent distances.

Using the relation between length and width:

L=W+8\\L=21.4+8=29.4

<em>Therefore, the dimensions of the pool are 29.4 length and 21.4 width.</em>

7 0
3 years ago
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