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2 years ago

Help me !!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Sveta_85 [38]2 years ago

5 0

Answer:4/125

Step-by-step explanation:

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Which shows the inequality for numbers at least 70?

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2 years ago

Which of the following statements correctly describes the position of the intake and exhaust valves during most of the power sta

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D. Both the intake valve and the exhust valve are closed.

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2 years ago

Read 2 more answers

Can someone please help me.

Katena32 [7]

Given
- f(n) values for n=1,2,3,4
- possible candidates for the function

Solution:
Method: Evaluate some of the values, for each function. A function with ANY value not matching the given f(n) values will be rejected.

N=1, f(n)=4
f(1)=4-3(1-1)=4
f(1)=4+3^(1+1)=4+3^2=4+9=13 ≠ 4 [rejected]
f(1)=4(3^(n-1))=4(3^0)=4
f(1)=3(4^(n-1))=3(4^0)=3*1=3 [rejected]

N=2, f(n)=12
f(1)=4-3(2-1)=4-3(1)=1 ≠ 12 [rejected]
[rejected]
f(1)=4(3^(2-1)=4*3^1=4*3=12
[rejected]

Will need to check one more to be sure
N=3, f(n)=3
[rejected]
[rejected]
f(3)=4(3^(n-1))=4(3^(3-1))=4(3^2)=4*9=36 [Good]
[rejected]

Solution: f(n)=4(3^(n-1))

6 0

3 years ago

Please help me out :)

arlik [135]

Answer:

$\frac{\sqrt{17} }{7}$

Step-by-step explanation:

Using the Pythagorean identity

sin²x + cos²x = 1, then

sinx = $\sqrt{1-cos^2x}$

Note that ( $\frac{4\sqrt{2} }{7}$ )² = $\frac{32}{49}$

sinΘ = $\sqrt{1-(32/49)}$

= $\sqrt{\frac{17}{49} }$ = $\frac{\sqrt{17} }{7}$

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2 years ago

The life of a manufacturer's compact fluorescent light bulbs is normal, with mean 12,000 hours and standard deviation 2,000 hour

vitfil [10]

Z value is a numerical measurement that describe a value relationship to the mean of a group of values. The standard deviations is 1.25 above the mean is 14,500 hours.

<h3>Given information-</h3>

The mean for the bulb is 12,000 hours.

The standard deviation for the bulb is 2000 hours.

Sample value is 14500.

To find out the how many standard deviation is 14500 mean away from the mean the z value of the mean should be calculated.

<h3>Z value</h3>

Z value is a numerical measurement that describe a value relationship to the mean of a group of values. Z value is the ratio of the difference of the sample value $x$ and mean $\mu$ to the standard deviation. Thus the z value for the given mean $\sigma$ is,

$z=\dfrac{x-\mu}{\sigma}$

$z=\dfrac{14500-1200}{2000}$

$z=1.25$

Thus the standard deviations is 1.25 above the mean is 14,500 hours.

Learn more about the z value here;

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4 0

2 years ago