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Rashid [163]
3 years ago
10

Emily catches the school bus at 7:45 am she needs 30 minutes to get dressed 15 minutes to eat breakfasts, an 10 minutes to walk

to the school bus . What latest time Emily can awake in the morning to get to the bus on time?
Mathematics
2 answers:
nika2105 [10]3 years ago
6 0

Answer:

6:50 am

Step-by-step explanation:

emily need 45 minutes to get dressed and eat breakfast which makes the time 7:00am then needs an extra 10 minutes to walk to school, therefore she needs to wake at 6:50am

just olya [345]3 years ago
5 0
6:50. If she wakes up at 6:50, and uses 30 minutes to get dressed, the time would be 7:20. Then if she uses 15 minutes to eat, the time would be 7:35. Lastly, if she uses her 10 minutes to walk, she’d catch the bus at 7:45. I don’t know why anyone would test their luck with that time, but that’s the answer. 6:50
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A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th
Burka [1]

Answer:

Confidence interval : 21.506 to 24.493

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = \bar{x}=\frac{\sum x}{n}

Sample mean = \bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}

Sample mean = \bar{x}=23

Sample standard deviation = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}

Sample standard deviation = \sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}

Sample standard deviation= s = 1.72

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table t_{\frac{\alpha}{2} = 3.883

Formula of confidence interval : \bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}

Substitute the values in the formula

Confidence interval : 23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}

Confidence interval : 23 -3.883 \times \frac{1.72}{\sqrt{20}} to 23 + 3.883 \times \frac{1.72}{\sqrt{20}}

Confidence interval : 21.506 to 24.493

Hence Confidence interval : 21.506 to 24.493

3 0
4 years ago
Read 2 more answers
A concert hall seats 802 people in the balcony and 6887 on the main floor there were a concert in June and the ticket was sold f
tatuchka [14]

Answer: 7689 tickets

Step-by-step explanation:

Since tickets was sold for every seat, the total number of tickets that were sold will be the addition of the 802 seats in the balcony and 6887 seats on the main floor. This will be:

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= 7689 tickets

5 0
3 years ago
PLEASE HELP! FIRST ANSWER GETS POINTS AND MARKED BRAINLIEST. If joe has 13 pieces of art but his teacher tells him to make 13 ti
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Answer: 169 more?

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8 0
3 years ago
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san4es73 [151]

Answer:

x = 125 ft and y = 250/3 ft

Step-by-step explanation:

Let assume that,

x be the length of the northern part of the fence (parallel to the north wall)

y be the length of the western and eastern pieces of the fence

As well as farmer has $4000 to spend hence we can write,

8x + 8y + 4y = 4000

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we can write

A'(x) = \frac{500}{3} -\frac{4x}{3}

equating it 0 we get

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x=125

Also,

A"(x) = -\frac{4}{3}

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we can see that A''(x) is always less than 0 hence using second derivative test we can say that x = 125 is a maximum point.

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Hence we can say that dimensions for the plot that would enclose the most area is,

x = 125 ft and y = 250/3 ft

5 0
4 years ago
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