Answer:
5lb of m&mns and 6lb of raisinets
Step-by-step explanation:
5lb x 2$ = $10
6lb x 1.5 = $9
<em>*To solve for a specified variable, you need to isolate that variable onto one side.</em>
<h3>11.</h3>
Firstly, subtract 5r on both sides: 
Lastly, divide both sides by 2 and <u>your answer will be
</u>
<h3>12.</h3>
First, subtract z on both sides of the equation: 
Next, divide both sides by y and <u>your answer will be
</u>
<h3>13.</h3>
Firstly, multiply both sides by b: 
Next, divide both sides by c and <u>your answer will be
</u>
ab+bc>can is the correct answer
Answer:
Anna's walk as a vector representation is
and refer attachment.
Step-by-step explanation:
Let the origin be the point 1 from where Ann start walking.
Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,
Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)
Ann walk as a vector representation is 
Thus, Anna's walk as a vector representation is 
Answer:
Correct answer is option D. 96.4 yd.
Step-by-step explanation:
Please refer to the attached figure for labeling of the given diagram.
ABC is a triangle with the following labeling:
A is the hole, B is the Tee and C is the point where the ball is.
Sides are labeled as:

To find:
Side 
Solution:
Here, we have one angle and two sides . Third side of the triangle is to be found opposite to the given angle.
We can use cosine formula here to find the value of the unknown side.

Putting all the values:

So, the distance between the Ball and hole is 96.42 yd
Correct answer is option D. 96.4 yd.