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aleksklad [387]
3 years ago
10

Assume that in a particular military exercise involving two units, Red and Blue, thereis a 60 % chance that the Red unit will su

ccessfully meet its objectives and a 70% chance that the Blue unit will do so. There is an 18 % chance that only theRed unit will be successful. What is the probability that both units will meet theirobjectives? What is the probability that one or the other but not both of the unitswill be successful?
Mathematics
1 answer:
Marysya12 [62]3 years ago
6 0

Answer: a) There are 42% chances that both units will meet their objectives.

b) There are 88% chances that one or the other but not both of the units will be successful.

Step-by-step explanation:

Since we have given that

Probability that the Red unit will successfully meet its objectives = 60% = P(R)

Probability that Blue unit will successfully meet its objectives = 70% = P(B)

Probability that only Red unit will be successful = P(only Red) = 18%

As we know that

P(only\ red)=P(R)-P(R\cap B)\\\\0.18=0.60-P(R\cap B)\\\\0.18-0.60=-P(R\cap B)\\\\-0.42=-P(R\cap B)\\\\P(R\cap B)=42\%

Hence, there are 42% chances that both units will meet their objectives.

the probability that one or the other but not both of the units will be successful is given by

P(R\cup B)=P(R)+P(B)-P(R\cap B)\\\\P(R\cup B)=0.60+0.70-0.42\\\\P(R\cup B)=0.88\\\\P(R\cup B)=88\%

Hence, there are 88% chances that one or the other but not both of the units will be successful.

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Need help with my homework ​
Volgvan

Answer:

\displaystyle y=\frac{16-9x^3}{2x^3 - 3}

\displaystyle y=-\frac{56}{13}

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3

Simplify the radical with the cube:

\displaystyle x^3=\frac{3y+16}{2y+9}

Multiply by 2y+9

\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)

Simplify:

\displaystyle x^3(2y+9)=3y+16

Operate the parentheses:

\displaystyle x^3(2y)+x^3(9)=3y+16

\displaystyle 2x^3y+9x^3=3y+16

Subtract 3y and 9x^3:

\displaystyle 2x^3y - 3y=16-9x^3

Factor y out of the left side:

\displaystyle y(2x^3 - 3)=16-9x^3

Divide by 2x^3 - 3:

\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}

ii) To find y when x=2, substitute:

\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}

\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}

\displaystyle y=\frac{16-72}{16- 3}

\displaystyle y=\frac{-56}{13}

\mathbf{\displaystyle y=-\frac{56}{13}}

8 0
3 years ago
Which graph represents the solution set of the system of inequalities?
Nimfa-mama [501]
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The second one (2y ≥ x - 4) will be changed to   y <span>≥ x/2 - 2.
Now we can analyze each graph.
In every single graph the first equation (y < -x + 1) is graphed correctly.
Now for the second equation, we can see that only the first and last graph correctly format to the equation.
Now for the shading:
The first equation shows us that y is less than -x +1, making the shading go under the dotted line. (to the left)
The second equation shows us that y is greater than or equal to x/2 - 2, making the shading go above the line. (also to the left)
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Answer:

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Step-by-step explanation:

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This graph also has one x-intercept at x=-3.

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Step-by-step explanation: see attachment

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myrzilka [38]
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