PLZ HELP IM STRUGGLING IM TIMED!! Find the area
2 answers:
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Answer:
Plese read the complete procedure below:
Step-by-step explanation:
The polynomial is p(a) = (a^4 - 6a^3 + 3a^2 + 26a – 24)
a)
1 -6 3 26 -24 |<u> 1 </u>
<u> 1 -5 -2 24</u>
1 -5 -2 24 0
The remainder is zero, then (a-1) is a factor of the polynomial
b)
1 -6 3 26 -24 |<u> 2 </u>
<u> 2 -8 10 72</u>
1 -4 5 36 48
When p(a) is divided by (a-2) the remainder 28/p(a)
1 -6 3 26 -24 |<u> - 4 </u>
<u> -4 40 172 -792</u>
1 -10 43 198 -816
When p(a) is divided by (a-2) the remainder -816/p(a)
c) I attached an image of the long division below:
Question 1:
Multiply both sides of the proportion by 35.
You get.
7(x-1) = 4x+2
7x-7 = 4x+2
Now, add both sides by 7 and subtract both sides by 4x
3x = 9
Divide both sides by 3
x=3
Question 2:
Multiply both the numerator and the denominator of
by 3.
We want to multiply it by 3 so that the +1 and +3 become +3 and +9. +3 and +9 have a difference of 6, just like 15 and 21, which is what we want.
Set the numerator equal to the numerator and the denominator equal to the denominator.
3x+3 = 15
3x+9 = 21
If you solve both of these, you get x=4 for both.
That's your answer.
Hope this helps! :)
Multiply both sides of the proportion by 35.
You get.
7(x-1) = 4x+2
7x-7 = 4x+2
Now, add both sides by 7 and subtract both sides by 4x
3x = 9
Divide both sides by 3
x=3
Question 2:
Multiply both the numerator and the denominator of
We want to multiply it by 3 so that the +1 and +3 become +3 and +9. +3 and +9 have a difference of 6, just like 15 and 21, which is what we want.
Set the numerator equal to the numerator and the denominator equal to the denominator.
3x+3 = 15
3x+9 = 21
If you solve both of these, you get x=4 for both.
That's your answer.
Hope this helps! :)