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2 years ago

There is no chart to go with this so please don't delete my question

Mathematics

1 answer:

tensa zangetsu [6.8K]2 years ago

5 0

Answer:

No. Jackson failed to account for possible alternate explanations.

Step-by-step explanation:

Both the watering schedule and the amount of sunlight may be contributors to the result Jackson observed. Without some way to control for these factors, the experiment is inconclusive regarding the contribution to the results that is made by the planting soil.

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A line with (5,6) and a slope of 2/15

BlackZzzverrR [31]

Slope, shmlope. What's the q?

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3 years ago

How do you use distributive property for 12(52)-12(62)

ololo11 [35]

Answer:

-120 , split it into diferent parts.

Step-by-step explanation:

12 (52) - 12 (62) = ?

12 x 52 = 624

12 x 62 = 744

624 - 744 = -120

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3 years ago

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Umnica [9.8K]

Step-by-step explanation:

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3 years ago

The length of each side of a square was decreased by 2 inches so the perimeter is now 49 inches. What was the original length of

aleksley [76]

The Original length of each side of square was 14.25 inches.

Step-by-step explanation:

Perimeter of a square is given by:

Perimeter = 4 * side

Let x be the original length of each side of square

decreasing 2 inch will mean

$x-2$

Perimeter of square after reducing 2 inches from each side

$4(x-2) = 49\\4x-8 = 49\\4x = 49+8\\4x = 57\\\frac{4x}{4} = \frac{57}{4}\\x = 14.25$

So,

The Original length of each side of square was 14.25 inches.

Keywords: Perimeter, square

Learn more about perimeter at:

#LearnwithBrainly

5 0

3 years ago

Solve the following equation. X cubed minus 6X squared plus 6X equals zero

anyanavicka [17]

We have to solve this equation:

$x^3-6x^2+6x=0$

Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:

$\begin{gathered} x^3-6x^2+6x=0 \\ x(x^2-6x+6)=0 \end{gathered}$

Now we can find the roots of the quadratic polynomial as:

$\begin{gathered} x=\frac{-(-6)\pm\sqrt[]{(-6)^2-4\cdot1\cdot6}}{2\cdot1} \\ x=\frac{6\pm\sqrt[]{36-24}}{2} \\ x=\frac{6\pm\sqrt[]{12}}{2} \\ x=\frac{6\pm\sqrt[]{4\cdot3}}{2} \\ x=\frac{6\pm2\sqrt[]{3}}{2} \\ x=3\pm\sqrt[]{3} \\ x_1=3-\sqrt[]{3} \\ x_2=3+\sqrt[]{3} \end{gathered}$

Then, the solutions to the equation are:

x = 0

x = 3 - √3

x = 3 + √3

4 0

1 year ago