Answer:
Option b (remain unnoticed so they can continue to steal data) is the right approach.
Explanation:
- APT seems to be sustained but instead designed to target coordinated attack whereby an attacker achieves network access including a longer length of time impossible to conceive.
- Usually, APT assaults become targeted at organizations throughout fields including such national security, engineering, as well as the financial services industry, as they make increased-value details.
There are 3 other possibilities not relevant to just the given case. So that the option here was the right one.
The email addresses or domains on a blacklist are automatically marked as spam in the inbox.
<h3>What is an email address?</h3>
A virtual address, which is unique in case of each individual and cannot be replicated for the purpose of sending and receiving mails and attachments, is known as an email address.
Hence, option A holds true regarding an email address.
Learn more about an email address here:
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Answer
Windows corrupted
Explanation:
Try buying a new windows or resetting your laptop/pc
or your service failed to register/start
Answer:
i cloud
Explanation:
but if you dont gota paypal youd want to get like an std card or somthime
Answer:
void mn(int m, int n){
int sum = 0;
int count = 0;
if(m<n){
for(int i = m;i<=n;i++){
sum+=i;
}
}
else{
for(int i = n;i<=m;i++){
sum+=i;
}
}
count = abs(m - n)+1;
cout<<"Sum: "<<sum<<endl;
cout<<"Average: "<<(float)sum/count;
}
Explanation:
This line defines the method
void mn(int m, int n){
This initializes sum and count to 0
int sum = 0;
int count = 0;
This checks if m is less than n
if(m<n){
This iterates from m to n and calculates the sum of numbers between this interval
<em> for(int i = m;i<=n;i++){</em>
<em> sum+=i;</em>
<em> }</em>
<em> }</em>
If otherwise,
else{
This iterates from n to m and calculates the sum of numbers between this interval
<em> for(int i = n;i<=m;i++){</em>
<em> sum+=i;</em>
<em> }</em>
<em> }</em>
This calculates the range from m to n using absolute function
count = abs(m - n)+1;
This prints the calculated sum
cout<<"Sum: "<<sum<<endl;
This calculates and prints the average
cout<<"Average: "<<(float)sum/count;
}
<em>See attachment for complete program that includes the main (in c++)</em>
