Factors of 80: 1,2,4,5,8,10,16,20,40,80
so we cross out 1,2,4,5,8,10,16
the first 5 multiples of 3 are: 3,6,9,12,15
so we cross out those number and then we are left with 7, 11, 13 and 14
the answer is: 4 numbers were not crossed out
Answer:
Statement of the given problem,
A shopkeeper made 20% profit on selling a bicycle at the labelled price but he would gain only Rs. 180 when 5% discount was allowed. What was the cost price of the bicycle?
Let C & M denote the required cost price & marked price respectively of the given bicycle.
Hence from above data we get following relations,
M = (1 + 20/100)*C
or M = (6/5)*C
(1 - 5/100)*M = 180 + C
or (19/20)*M = 180 + C
or (19/20)*(6/5)*C = 180 + C
or (57/50)*C - C = 180
or (7/50)*C = 180
or C = (50/7)*180 = 1285.71
You need to set up ratios to solve for x. It's all about proportions here. I'm going to set up the ratio with the smaller triangle stuff (the one on the left) on top and the larger triangle stuff on bottom. Corresponding sides rule the day.
. Cross-multiply to solve for x. 12x=144 and x = 12.
7 out of 9 , 7:9, 7/9
because 4+5=9
9-2= 7
Answer:
c) 4
The value of z= 4
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given equations are
3x - y =16 .. . (i)
3x -4z =2 .. . (ii)
2x +y = 14 .. .(iii)
solving (i) and (ii) equations , we get
Adding (i) and (ii)
3 x -y + 2x +y = 16 +14
5 x = 30
x = 6
<u><em>step(ii):-</em></u>
Substitute 'x' =6 in equation (i), we get
3(6) -y =16
18 - 16 =y
y = 2
x =6 and y =2
substitute x=6 in equation (ii) , we get
3 (6) - 4 z = 2
18 - 2 = 4 z
16 = 4 z
z = 4
<u><em>Final answer:-</em></u>
x = 6 , y = 2 and z =4