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Gnom [1K]
2 years ago
9

Solve the given system by substitution.

Mathematics
2 answers:
denis-greek [22]2 years ago
8 0

Answer:

Step-by-step explanation:

5m = 2/3m - 13

15m = 2m - 39

13m = -39

m = -3

n = 5(-3)

n = -15

(-3, -15)

alekssr [168]2 years ago
4 0

Answer:

(-3, -15)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

n = 5m

n = 2/3m - 13

<u>Step 2: Solve for </u><em><u>m</u></em>

<em>Substitution</em>

  1. Substitute in <em>n</em>:                                 5m = 2/3m - 13
  2. Subtract 2/3m on both sides:          13/3m = -13
  3. Divide 11/3 on both sides:                m = -3

<u>Step 3: Solve for </u><em><u>n</u></em>

  1. Define equation:                    n = 5m
  2. Substitute in <em>m</em>:                      n = 5(-3)
  3. Multiply:                                  n = -15
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What is each power of i with its multiplicative inverse.
pentagon [3]

Answer:

1) multiplicative inverse of i = -i

2) Multiplicative inverse of i^2 = -1

3) Multiplicative inverse of i^3 = i

4) Multiplicative inverse of i^4 = 1

Step-by-step explanation:

We have to find multiplicative inverse of each of the following.

1) i

The multiplicative inverse is 1/i

if i is in the denominator we find their conjugate

=1/i * i/i\\=i/i^2\\=We\,\, know\,\, that\,\, i^2 = -1\\=i/(-1)\\= -i

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The multiplicative inverse is 1/i^4

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so, Multiplicative inverse of i^4 = 1

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3 years ago
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