In this case the temperature depends on the hour. So temperature is your X and hour is your Y variable. When h=0, x=0. So the 21*C is you x=0 or y-int point.
If we are trying to match the equation for a line of y=mx+b, 21*C=b.
Our rate of change is -4*C/h, which is our m variable.
So y=(-4)x+(21)
OR in this case, t=-4h+21.
Answer D.
Answer:
Not a Function.... hope you pass!
Answer: -7/3≤t≤5/3
Step-by-step explanation:
|2t + 2/3|≤4
2t + 2/3≤4
(2t + 2/3≤4)*3
6t+2≤12
6t≤10
t≤10/6
<u>t≤5/3</u>
2t + 2/3>=-4
(2t + 2/3>=-4)*3
6t + 2>=-12
6t>=-14
t>=-14/6
<u>t>=-7/3</u>
-7/3≤t≤5/3