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Ostrovityanka [42]
2 years ago
7

A population has a mean of 300 and a standard deviation of 18. A sample of 144 observations will be taken. The probability that

the sample mean will be between 297 to 303 is
Mathematics
1 answer:
erastova [34]2 years ago
3 0

Answer:

0.8664

Step-by-step explanation:

I hope it helps, and please give me Brainlest!

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3 years ago
A line’s equation is given in point-slope form:
navik [9.2K]

we conclude that the point on this line that is apparent from the given equation is (-6, 6)

<h3>Which point is on the line, only by looking at the equation?</h3>

Remember that a general linear equation in slope-intercept form is:

y = a*x + b

Where a is the slope.

Here we have the linear equation:

y - 6= (-23)*(x + 6)

Now, for a linear equation with a slope a and a point (h, k), the point slope form of the linear equation is:

(y - k) = a*(x - h)

Now we can compare that general form with our equation, we will get:

(y - k) = a*(x - h)

(y - 6) = (-23)*(x + 6)

Then we have: k  = 6 and h = -6.

Thus, we conclude that the point on this line that is apparent from the given equation is (-6, 6).

If you want to learn more about linear equations:

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4 0
1 year ago
Shane wants to plant 28 marigold plants and 36 rose plants in his garden. What is the greatest number of rows possible if each r
Dennis_Churaev [7]

Answer:

HCF=2*2=4

Step-by-step explanation:

Given :   Shane wants to plant 28 marigold plants and 36 rose plants in his garden  

To Find :  the greatest number of rows possible  each row has the same

number of marigold plants and the same number of rose plants.​

Solution:

marigold plants  = 28

rose plants = 36

To find  the greatest number of rows possible  if each row has the same

number of marigold plants and the same number of rose plants.​

we need to find HCF of 28 and 36

28 = 2 x 2 x 7

36 = 2 x 2 x 3 x 3

HCF = 2 x 2  = 4

greatest number of rows possible  is 4

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6 0
2 years ago
Why does beethoven now spend all his time erasing music
schepotkina [342]
He is decomposing :0
3 0
3 years ago
Let f(x)=241+3e−1.3x . What is the point of maximum growth rate for the logistic function f(x) ? Round your answer to the neares
FromTheMoon [43]

Answer:

The point of maximum growth is at x=0.82

Step-by-step explanation:

Given a logistic function

f(x)=\frac{24}{1+e^{-1.3x}}

we have to find the point of maximum growth rate for the logistic function f(x).

From the graph we can see that the carrying capacity or the maximum value of logistic function f(x) is 24 and the point of maximum growth is at y=\frac{24}{2} i.e between 0 to 12

So, we can take y=\frac{24}{2} and then solve for x.

\frac{24}{2}=\frac{24}{1+e^{-1.3x}}

⇒ 2=1+3\exp{-1.3x}

⇒ 1=3.\exp{-1.3x} ⇒ \frac{1}{3}=\exp{-1.3x}

                             ⇒ log 3=-1.3x

                             ⇒ -0.4771=-1.3.x ⇒ x=0.82

Hence, the point of maximum growth is at x=0.82


5 0
3 years ago
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