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Daniel [21]
3 years ago
10

What is the explicit formula for this sequence?-6 -1 4 9 14​

Mathematics
1 answer:
kogti [31]3 years ago
4 0
The answer is B, (plus 5)
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A. B. AB ≅ AC<br> C. D. CS ≅ ST
Lemur [1.5K]

Answer:

what are the rest of the choices, if the ones are the top ones they dont make sense.

Step-by-step explanation:

4 0
2 years ago
Find a​ point-slope form for the line with slope 1/5 ( 1 over 5) and passing through the point ​(−8​,−9​)
leva [86]

Answer:

y + 9 = 1/5(x + 8)

Step-by-step explanation:

Point-slope form: y - y₁ = m(x - x₁)

Substitute the values into the equation.

y - (-9) = 1/5(x - (-8)

y + 9 = 1/5(x + 8)

7 0
2 years ago
The height (in ft) of an object over time(in seconds) is modeled by the function h(t)=-6t^2+23t+7. How high is the object after
riadik2000 [5.3K]

About 4.1 seconds. How long was the ball in the air? We are told that t represents time in seconds since the ball was thrown, so it started to be 'in the air' at t = 0 To answer the question, then, we need to know the time when it stopped being in the air. We are told that the ball hit the ground. So that's what happened when it stopped being airborne. We need to relate that event to the mathematics we're working with. What can we say about h , the height of the ball when the ball hits the ground? Answer: The height will be 0 when the ball stops being in the air. Now translate this back to the mathematics: The ball is in the air from t = 0 until the time t when h = 0 . Find the time t that makes h = 0 . That means: solve: − 5 t 2 + 20 t + 2 = 0 We can solve this by solving: 5 t 2 − 20 t − 2 = 0 (Either multiply both sides of the equation by − 1 , or add 5 x 2 − 20 x and − 2 to both sides and then re-write it the other way around) That's a quadratic equation, so try to factor first. But don't spend too much time trying to factor, because not every quadratic is easily factorable and that's OK, because we still have the quadratic formula if we need it. We do need it. t = − ( − 20 ) ± √ ( − 20 ) 2 − 4 ( 5 ) ( − 2 ) 2 ( 5 ) = 20 ± √ 440 10 = 20 ± √ 4 ( 110 ) 10 = 20 ± 2 √ 110 10 = 2 ( 10 ± √ 110 ) 2 ( 5 ) = 10 ± √ 110 5 We can see that 10 < √ 110 < 11 . In fact ( 10 + 1 2 ) 2 = 10 2 + 10 + 1 4 = 110.25 Using 10.25 as an approximation for √ 110 , we get : for the solution t = 10 − √ 110 5 we'll get a negative t . That doesn't make sense. The other solution gives t ≈ 10 + 10.25 5 = 20.5 5 = 4.1 seconds. So the ball was in the air from t = 0 until about t = 4.1 . The elapsed time is the difference, 4.1 seconds.

5 0
2 years ago
Write the contrapositive of the conditional statement. If it is January, then there are 31 days this month.
kifflom [539]
If there aren't 31 days this month, then it isn't January. 

Hope this helps!
5 0
3 years ago
Read 2 more answers
Find the quotient 3/4÷1 1/10
Scorpion4ik [409]

Answer:

15/22

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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