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LenaWriter [7]
3 years ago
10

I'm having trouble solving this, if anyone could help I'd be most appreciated.

Mathematics
1 answer:
STALIN [3.7K]3 years ago
5 0
You can check that
f(1)=0
f(-3)=0
f(-5)=0

thus:
x^3+7x^2+7x-15=\boxed{(x-1)(x+3)(x+5)}

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Why does it take more centimeters than inches to measure the same distance?
MaRussiya [10]
Because 1 centimeter is smaller than 1 inch, so more centimeters than inches can fit in a given distance. 
6 0
3 years ago
Hey can I have some help please?<br><br> Is this answer correct? Or is it the third one?
Lubov Fominskaja [6]

Answer:

I would say you are correct

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The graphs below are based on government data on unemployment for 2017.
lord [1]

You already got the first two questions right: the group with the highest number of people unemployed / unemployment rate is the one with the highest bar in the respective histogram.

The two graph are related in this sense: take the first age group as reference. We know that 700 people from 16 to 19 are unemployed, and that those people represent 14% of the population, then we know that the 14% of the population between 16 and 19 is 700.

We can deduce that, if x is the number of people between 16 and 19, we have

\dfrac{14}{100}x=700 \iff \dfrac{7}{50}x=700 \iff \dfrac{x}{50}=100 \iff x=5000

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3 0
3 years ago
Write an expression for the operation described below.<br><br><br> multiply 6 by u
Masteriza [31]

Answer:

6u

Step-by-step explanation:

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4 0
3 years ago
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Five more than the quotient of a number and 3 equals 2.
MakcuM [25]

Answer:

\large\boxed{\dfrac{n}{3}+5=2\ or\ n:3+5=2}

Step-by-step explanation:

\dfrac{n}{3}+5=2\\\\\dfrac{n}{3}-\text{the quotient of a number}\ n\ \text{ and 3}\\\\...+5-\text{five more than}

If you want a solution:

\dfrac{n}{3}+5=2          <em>subtract 5 from both sides</em>

\dfrac{n}{3}+5-5=2-5

\dfrac{n}{3}=-3            <em>multiply both sides by 3</em>

3\!\!\!\!\diagup\cdot\dfrac{n}{3\!\!\!\!\diagup}=(3)(-3)\\\\n=-9

4 0
3 years ago
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