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Zinaida [17]
2 years ago
11

If 3 is added to the absolute value of the product of a number and –9, the result is 4.

Mathematics
1 answer:
omeli [17]2 years ago
8 0

Answer:

± (1 ÷ 9)

Step-by-step explanation:

Data provided in the question

Since  3 is added to the absolute value and -9

The result is 4

Now this information should be transformed in a mathematical equation

Let us assume be x so the product of the number and -9 be -9x

Fo rthe absolute value we use the mode. Thus the required expression is:

3 + |-9x|

Given that the result is 4

So, it would be

3 + |-9x| = 4

Now Solving the above equation which is given below:

|-9x| = 4-3

|-9x| = 1

here we will remove the mode by introducing ± sign which is shown below:

-9x = ± 1

-9x = 1 or -9x = -1

x = -1/9

or

x = \frac{1}{9}

Therefore, the value of x is ± (1 ÷ 9).

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Answer:

25 hamburger

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Step-by-step explanation:

7 0
2 years ago
Ab= <br> round to the nearest hundredth
mestny [16]
Cos = adjacent / hypotenuse

cos 25° = 4 / AB

cos 25° • AB = 4 / AB • AB

AB cos 25° ÷ cos 25° = 4 ÷ cos 25°

AB = 4/cos 25°

AB = 4.41 (nearest hundredth)
8 0
3 years ago
A 10 foot ladder is leaning up against a building. If the ladder makes a 46° angle
Gnesinka [82]

Answer:

7.193 ft

Step-by-step explanation:

    |\

    |   \

    |      \

    |         \

h  |            \      10 ft

    |               \

    |                  \

    |            46°   \

    ---------------------

For the 46° angle, h is the opposite leg. The hypotenuse is 10 ft. The sine is the trig ratio that relates the opposite leg to the hypotenuse.

sin A = opp/hyp

sin 46° = h/10

h = 10 sin 46°

h = 7.193

Answer: 7.193 ft

4 0
2 years ago
The first term of an arithmetic sequence is 7 and the sixth term is 22. Find(a)the common difference;(2)(b)the twelfth term;(2)(
SVEN [57.7K]

d = 3 , a₁₂ = 40 and Sx_{100} = 7775

In an arithmetic sequence the nth term and sum to n terms are

<h3>• an = a₁ + (n-1)d</h3><h3>• S_n = \frac{n}{2}[2a + (n-1)d]</h3><h3>where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ = \frac{50}{2}[(2×7) +(99×3)</h3><h3>       = 25(14 + 297) = 25(311)= 7775</h3>
7 0
2 years ago
Please solve the system of equations below thank you<br> explain if u can
ivanzaharov [21]
First let’s try to cancel out the x
5x + -5x = 0
Add the y and the numbers together
-3y + -2y = -5y
26 + -16 = 10
-5y = 10
y = -2
Use y=-2 in one of the equations
-3(-2) + 5x = 26
6 + 5x = 26
5x = 20
X = 4

So
Y= -2
X= 4

https://mathsmadeeasy.co.uk/gcse-maths-revision/simultaneous-equations-gcse-maths-revision/

Check this link out for more help!
7 0
2 years ago
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