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Bess [88]
3 years ago
12

Help me with n.7 please

Mathematics
2 answers:
Mandarinka [93]3 years ago
8 0
Your answer should be a
gulaghasi [49]3 years ago
7 0

Answer:

It would be the first answer well first blank dot

Step-by-step explanation:

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A student gets 5 problems correct out of every 10 problems. If the student answers a total of 60 problems on the test how many w
NeTakaya

Answer:

30 correct

Step-by-step explanation:

60 / 10 = 6

6 * 5 = 30

8 0
3 years ago
Read 2 more answers
A phone plan charges $15.95 per month and $0.10 for every minute, m, that the phone is used. Mr. Kordemsky wants his phone bill
aleksandrvk [35]

Answer:

The inequality that could be used to model this situation is 15.95+0.10m<40. Also, the number of minutes has to be less than 240.5 for Mr. Kordemsky's phone bill for the month to be less than $40.

Step-by-step explanation:

From the information provided, the inequality would indicate that the phone bill for the month that is equal to the result of the fixed fee plus the price per minute for the number of minutes has to be less than $40, which can be expressed as:

15.95+0.10m<40

Now, you can solve for m:

15.95+0.10m<40

0.10m<40-15.95

0.10m<24.05

m<24.05/0.10

m<240.5

According to this, the answer is that the inequality that could be used to model this situation is 15.95+0.10m<40. Also, the number of minutes has to be less than 240.5 for Mr. Kordemsky's phone bill for the month to be less than $40.

6 0
3 years ago
Х- а<br>x-b<br>If f(x) = b.x-a÷b-a + a.x-b÷a - b<br>Prove that: f (a) + f(b) = f (a + b)​
GenaCL600 [577]

Given:

Consider the given function:

f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot(x-b)}{a-b}

To prove:

f(a)+f(b)=f(a+b)

Solution:

We have,

f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot (x-b)}{a-b}

Substituting x=a, we get

f(a)=\dfrac{b\cdot(a-a)}{b-a}+\dfrac{a\cdot (a-b)}{a-b}

f(a)=\dfrac{b\cdot 0}{b-a}+\dfrac{a}{1}

f(a)=0+a

f(a)=a

Substituting x=b, we get

f(b)=\dfrac{b\cdot(b-a)}{b-a}+\dfrac{a\cdot (b-b)}{a-b}

f(b)=\dfrac{b}{1}+\dfrac{a\cdot 0}{a-b}

f(b)=b+0

f(b)=b

Substituting x=a+b, we get

f(a+b)=\dfrac{b\cdot(a+b-a)}{b-a}+\dfrac{a\cdot (a+b-b)}{a-b}

f(a+b)=\dfrac{b\cdot (b)}{b-a}+\dfrac{a\cdot (a)}{-(b-a)}

f(a+b)=\dfrac{b^2}{b-a}-\dfrac{a^2}{b-a}

f(a+b)=\dfrac{b^2-a^2}{b-a}

Using the algebraic formula, we get

f(a+b)=\dfrac{(b-a)(b+a)}{b-a}          [\because b^2-a^2=(b-a)(b+a)]

f(a+b)=b+a

f(a+b)=a+b               [Commutative property of addition]

Now,

LHS=f(a)+f(b)

LHS=a+b

LHS=f(a+b)

LHS=RHS

Hence proved.

5 0
3 years ago
Which of the following is equivalent to the expression below?<br> (5+1) + (7 - 41)
Strike441 [17]

Answer:

-28

Step-by-step explanation:

6+(-34)

6-34= -28 that is the simplified form though the question isnt clear

4 0
3 years ago
4.375, 4, 5, 3.75 least to greatest<br><br>​
LiRa [457]

Answer:

3.75, 4., 4.375., 5

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
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