1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bond [772]
3 years ago
15

PLS HELP

Mathematics
1 answer:
NemiM [27]3 years ago
5 0

it is 2y 1x, good luck, hope i helped!!!

You might be interested in
HELP PLEASE!!! 10 PTS!!
allsm [11]

Answer:

m∠DEC = 78°

Step-by-step explanation:

Given information: AC = AD, AB⊥BD, m∠DAC = 44° and CE bisects ∠ACD.

If two sides of a triangles are congruent then the opposite angles of congruent sides are congruent.

AC = AD                 (Given)

\angle ADC\cong \angle ACD

m\angle ADC=m\angle ACD

According to the angle sum property, the sum of interior angles of a triangle is 180°.

m\angle ADC+m\angle ACD+m\angle DAC=180

m\angle ACD+m\angle ACD+44=180

2m\angle ACD=180-44

2m\angle ACD=136

Divide both sides by 2.

m\angle ACD=68

CE bisects ∠ACD.

m\angle ACE=m\angle DCE=\dfrac{\angle ACD}{2}

m\angle ACE=m\angle DCE=\dfrac{68}{2}

m\angle ACE=m\angle DCE=34

Use angle sum property in triangle CDE,

m\angle CDE+m\angle DCE+m\angle DEC=180

68+34+m\angle DEC=180

68+34+m\angle DEC=180

102+m\angle DEC=180

Subtract 102 from both sides.

m\angle DEC=180-102

m\angle DEC=78

Therefore, the measure of angle DEC is 78°.

6 0
2 years ago
Simplify 8(xy + 8) + 1. 8xy + 9 8xy + 65 8xy + 73
mixer [17]

64x2y2 the twos are powers of ten so you put them up top.

8 0
3 years ago
Read 2 more answers
In one year the perseid metor shower had a metor appear every 1/5 5 minutes on average That same year the Leonid metor shower ha
olga55 [171]

In one year, the Perseid meteor shower had a meteor appear every 1 1/5 minutes on average. That same year, the Leonid meteor shower had a meteor appear every 4 2/3 minutes on average. How many more meteors fell during the Perseid meteor shower?

Answer:

325,452 meteors

Step-by-step explanation:

We all know that :

We have 365 days in a year and in each day there are 24 hours, Likewise an hour has 60 minutes

SO, the total number of minutes in a year is :

365 × 24 × 60 = 525600 minutes

For Perseid  meteor:

1 + \frac{1}{5}  \\ \\ = 1 + 0.2 \\  \\ = 1.2

So one meteor fall at 1.2 minutes interval Thus, in a year, we will have :

1 meteor - 1.2 minutes.

x meteor - 525600 minutes.

1.2x = 525600

x = \frac{525600}{1.2}

x = 438000

∴  438,000 meteors fell during the Perseid shower.

For  Leonid meteor shower:

4 + \frac{2}{3} = 4.67

So one meteor fall at 4.67 minutes interval Thus, in a year, we will have :

1 meteor - 4.67 minutes.

x meteors - 525600 minutes.

4.67x = 525600

x = \frac{525600}{4.67}

x = 112548

112,548 meteors fell during the Leonid Shower.

Finally , the numbers of more meteors that  fell during the Perseid meteor shower is calculated by the difference in the number of Perseid meteor shower and Lenoid meteor shower. i.e

438,000 - 112,548 = 325,452

325,452 more meteors fell during the Perseid meteor shower

5 0
3 years ago
Which of these points does not change its location when it is reflected across the y-axis? (2, 0) (0, 6) (3, 3) (–5, 5)
Anna [14]

Answer:

-5,5

Step-by-step explanation:

5 0
3 years ago
Pls help:Find all the missing elements:
Yuliya22 [10]

Answer:

<h3>B = 48.7° , C = 61.3° , b = 12</h3>

Step-by-step explanation:

In order to find B we must first angle C

To find angle C we use the sine rule

That's

\frac{ |a|  }{ \sin(A) }  =  \frac{ |c| }{ \sin(C) }

From the question

a = 15

A = 70°

c = 14

So we have

\frac{15}{ \sin(70) }  =  \frac{14}{ \sin(C) }

\sin(C)  =  \frac{14 \sin(7 0 ) }{15}

C = \sin^{ - 1} (  \frac{14 \sin(70) }{15} )

C = 61.288

<h3>C = 61.3° to the nearest tenth</h3>

Since we've found C we can use it to find B.

Angles in a triangle add up to 180°

To find B add A and C and subtract it from 180°

That's

A + B + C = 180

B = 180 - A - C

B = 180 - 70 - 61.3

<h3>B = 48.7° to the nearest tenth</h3>

To find b we can use the sine rule

That's

\frac{ |a| }{ \sin(A) }  =  \frac{ |a| }{ \sin(B) }

\frac{15}{ \sin(70) }  =  \frac{ |b| }{ \sin(48.7) }

|b|  =  \frac{15 \sin(48.7) }{ \sin(70) }

b = 11.9921

<h3>b = 12.0 to the nearest tenth</h3>

Hope this helps you

6 0
3 years ago
Other questions:
  • How would you do 5/12 multipled by 1/5 times 8
    5·2 answers
  • What is 80 divided by 3/5?
    9·1 answer
  • Which of the following equations shows direct variations a) y= x/3 + 1 B) y= 3x c) Y=3/x
    9·1 answer
  • Please help my sister with this
    5·1 answer
  • How would I solve a problem like this?
    11·1 answer
  • NOTE: ONLY FOR EXPERTS.... ONLY
    15·1 answer
  • If you could help me on all of them you a live saver
    15·1 answer
  • **IM TOO LAZY TO DO THIS MYSELF PLEASE HELP**<br><br> Round 6.43857 to the nearest ten thousandth.
    11·2 answers
  • Think! *
    15·1 answer
  • 60 points!!! Please answer immediately and the entire page please I will also give you five stars
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!