All categories

3 years ago

Help with math homework?

Mathematics

1 answer:

Ede4ka [16]3 years ago

4 0

Answer:

The range of the curve is $[-9,9]$ .

Step-by-step explanation:

The domain of the curve corresponds to the values on horizontal axis (x-Axis), where the range of curve corresponds to the values on vertical axis (y-Axis). In addition, the curve is continuous in $(-5, 8)$ , so that images exists within interval.

The range of the curve is $[-9,9]$ .

You might be interested in

Every _____ tessellates.

Ludmilka [50]

<span>Every hexagons tessellates. Hexagons always tessellates when perfectly combined and aligned especially when the x sides and the y sides are parallel to each other. An example of tessellating hexagons is bee hive. Bee hives have perfect tessellating hexagons.</span>

3 0

3 years ago

Read 2 more answers

Which two terms can be combined in this expression?

sammy [17]

$\left[\begin{array}{ccc}The&Answer&Should\\Be&The&Second\\Option&Good&bye\end{array}\right]$

------------------------------------------

5 0

3 years ago

Read 2 more answers

What is the equation 2/3a - 1/6= 1/3

Rashid [163]

Answer:

$a=\frac{3}{4}$

Step-by-step explanation:

I can't do the step-by-step explanation because my device is currently dying, But I am sure that $a=\frac{3}{4}$ is the correct answer.

5 0

3 years ago

Read 2 more answers

Please help me on this big question

STatiana [176]

Answer:

1.E, F

2. ↔ AE

3. X

4.Y

Step-by-step explanation:

4 0

3 years ago

How do you do this problem? I need to know how you found the answer.

Alexxandr [17]

to get the equation of a line, we simply need two points, say for the Red one ... notice in the graph the lines passes through (0,2) and (-1,6), so let's use those

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{-1-0}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-4(x-0) \\\\\\ y-2=-4x\implies \blacktriangleright y=-4x+2 \blacktriangleleft$

now, for the Blue one, say let's use hmmm it passes through (0,2) and (1.6)

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{1-0}\implies \cfrac{4}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=4(x-0) \\\\\\ y-2=4x\implies \blacktriangleright y=4x+2 \blacktriangleleft$

3 0

3 years ago

Help with math homework?​

Help with math homework?