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soldi70 [24.7K]
3 years ago
6

What is the equatipn of the linear graph? (-4, 6). (1, -9)

Mathematics
1 answer:
dusya [7]3 years ago
3 0

Answer:

y = -3x - 6

Step-by-step explanation:

first, find the slope

(-4, 6)

(1, -9)

remember the equation for the slope

\frac{y_{2}-y_{1}}{x_{2} - x_{1}} }

insert given points

x_{1} = -4\\y_{1} = 6\\\\x_{2} = 1\\y_{2} = -9

((-9) - (6)) / ((1) - (-4))

simplify

( -9 - 6) / (1 + 4)

= -15/ 5

= -3

now insert it into the equation of the line

remember, the equation of the line is

y = mx + b

where "m" is the slope

and "b" is the y-intercept

to find "b", you just have to plug in a point that is found on the line

we know that (-4, 6) and (1. -9) is found on the line, so let's just use (-4, 6) for this problem

y = mx + b

substitute in the slope of this line

y = -3x + b

now substitute in the given points

6 = -3 * -4 + b

and solve it like any algebra problem, by inverse operations and simplifying

6 = 12 + b

-12      -12

-6 = b

so the equation of the line is

y = -3x -6

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Step-by-step explanation:

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3 years ago
Which of the following is the graph of y=sqr root -x-3
Elan Coil [88]

Answer:

The graph in the attached figure

see the explanation

Step-by-step explanation:

we have

y=\sqrt{-x-3}

we know that

The radicand must be greater than or equal to zero

so

(-x-3)\geq 0

solve for x

Adds 3 both sides

-x\geq 0+3

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Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

x\leq -3

so

The domain of the function is the interval (-∞,-3]

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3 years ago
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konstantin123 [22]

Answer:

5000

Step-by-step explanation:

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3 years ago
-4+(5+6/-6×5)-2 extra stuff to ask question​
natta225 [31]

Answer:

Step-by-step explanation:

-4 + (5+6/ -6 × 5) -2

Solve the brackets first!

-4 + (11/ -30) -2

Add the -4 and -2

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[If you meant -2 multiplied by  (-11/30) then , something like this, If not then continue after the bracket!:

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(-60+11)/15

-49/15 Answer ]

Now,

-6 -11/30

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Hope this helps!

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Answer: a

hope this helps

3 0
3 years ago
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