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3 years ago

What is the constant variation of x-3 and y =27

Mathematics

1 answer:

Naily [24]3 years ago

4 0

-9 i believe because 9x3=27

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Find the value of 5.8 divided by 1.2

Katena32 [7]

It is easier to do if we get rid of the decimals, so lets multiply both numbers by 10:
5.8/1.2 = 58/12
and reduce the fraction:
= 29/6
then operate:
= 4.83

7 0

3 years ago

3 less than m is greater than 9

Artist 52 [7]

Answer:

m-9 = 3 is the required expression

5 0

3 years ago

Read 2 more answers

PLEASE HELP !!!! ILL GIVE BRAINLIEST !!!

luda_lava [24]

Answer:

113

Step-by-step explanation:

8 0

3 years ago

write an equation for the line that passes through the given point and has the given slope m (4,-5);m= -1/4

EastWind [94]

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Answer: $\textsf{y = -1/4x - 4}$

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Given: $\textsf{Slope = -1/4, Point through = (4, -5)}$

Find: $\textsf{Equation for the line that passes through the given point}$

Solution: In order to get the equation, we need to first use the point-slope form to help us sort out our information and then we solve for y.

<u>Plug in the values</u>

$\textsf{y - y}_1\textsf{ = m(x - x}_1\textsf{)}$

$\textsf{y - (-5) = -1/4(x - 4)}$

<u>Simplify and solve for y</u>

$\textsf{y + 5 = -1/4(x - 4)}$

$\textsf{y + 5 = -1/4x + 1}$

$\textsf{y + 5 - 5 = -1/4x + 1 - 5}$

$\textsf{y = -1/4x - 4}$

Therefore, the final answer would be that the equation that has a slope of -1/4 and passes through (4, -5) is y = -1/4x - 4.

5 0

2 years ago

Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho

Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

$X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )$

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, $P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10$

$P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]$

As, $P(z>1.28)=0.10$ [By z-table]

Then,

$\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712$

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0

4 years ago