Question

Two perpendicular lines intersect on the -axis. The equation of one line is y- 4x-6=0. Determine the equation of the other line.

Answer 1

Answer:

y = $-\frac{1}{4}$x + 6 or y = $-\frac{1}{4}$x - 0.375

Step-by-step explanation:

For 2 lines to be perpendicular, their slopes must be negative reciprocals. In order to find the perpendicular of y - 4x - 6 = 0:

SLOPE INTERCEPT FORM: y = 4x + 6

SLOPE OF LINE A: m=4

SLOPE OF LINE B (the one you are looking for): m=$-\frac{1}{4}$

Since I don't know if you meant that they intercept on the x or y axis I will do both.

y-axis

y-6=$-\frac{1}{4}$(x-0)

y = $-\frac{1}{4}$x+6

x-axis

y-0=$-\frac{1}{4}$(x-1.5)

y=$-\frac{1}{4}$x-0.375