Answer:
x = 5, y = 3
Step-by-step explanation:
<u>Elimination method: (I will be eliminating 4y) </u>
3x + 4y = 27 --- Equation 1
x + 4y = 17 --- Equation 2
Equation 1-2: 3x + 4y - x - 4y = 27 - 17
2x = 10
x = 10 ÷ 2
x = 5
Substitute x = 5 into Equation 2:
x + 4y = 17
4y + 5 = 17
4y = 17 - 5
= 12
y = 12 ÷ 4
y = 3
You may combine these 3 numbers in any order.
-19 -53 = -72, and then
-72 - 31 = -103.
You could combine -53 and -31 first, and then combine the result with -19.
Answer
given,
five balls numbered 1, 2, 3, 4, and 5.
two balls are drawn randomly
number of ways of selecting two balls = ⁵C₂ = 10 ways
For sample to be of largest number there is two option 4 or 5
so for first section of ball probability will be = 
now one ball is selected so for the selection of second ball the ball are 4
probability of second ball selection = 
a) largest of the two sample
= 
= 
=0.1
b) sum of two sample
= 
= 
= 0.65
So you would start with 40/n because quotient means division and then it would be (40/n) - 13 (40 divided by n then minus 13) because the answer is thirteen less than the quotient of those numbers. since it wants you to evaluate for n=2 you would do 40/2 which is 20 then subtract 13 which is 7.
So write the expression as (40/n) -13 and when you evaluate just stick the 2 where the n is for (40/2) - 13
20 - 13
= 7
Answer:
x=7
Step-by-step explanation:
