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Pavlova-9 [17]
3 years ago
8

Which statement is true about the distribution?

Mathematics
2 answers:
ozzi3 years ago
8 0

Answer with explanation:

Lowest Variate in distribution =10

Largest Variate in distribution =45

Range =Maximum Variate - Minimum Variate

       = 45 -10

       =35

→First Quartile

          Q_{1}=15

→Median =Q= 25

→Third Quartile

         Q_{3}=40

IQR=Inter Quartile Range

   =Q_{3}-Q_{1}\\\\=40-15\\\\=25

To calculate Outliers

\rightarrow Q_{3} + 1.5\times IQR=40 +1.5 \times 25\\\\=40 +3.75\\\\=43.75\\\\\rightarrow Q_{1} - 1.5\times IQR\\\\=15 - 1.5 \times 25\\\\=15 - 3.75\\\\=11.25

→Numbers below, 11.25 and numbers above 43.75 are outliers.

So, both , 10 and 45 , are outliers.

Therefore, range is not good measure of variability.

→→I QR , is better measure of Variability.

But , Option A,⇒ Either the IQR or the range are good measures of variability because the distribution has an outlier.

MissTica3 years ago
5 0

Answer:

it would be C. Either the IQR or the range are good measures of variability because the distribution has no outliers

Step-by-step explanation:

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Answer: D) 85

Step-by-step explanation:

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4 years ago
Can someone please help me answer these 2 questions with a full explanation so I can do the rest on my own? will give brainliest
Anton [14]

Answer:

a)  ∠ABC = 54°

a)  ∠ABC = 43°

Step-by-step explanation:

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

<u>Part (a)</u>

Use the cos trig ratio to find an expression for the measure of BD:

\implies \sf \cos (38^{\circ})=\dfrac{BD}{24.3}

\implies \sf BD=24.3\cos (38^{\circ})

Use the cos trig ratio and the found length of BD to find angle ABD:

\sf \implies \cos(ABD)=\dfrac{BD}{19.9}

\sf \implies \angle ABD=\cos^{-1}\left(\dfrac{24.3\cos (38^{\circ})}{19.9}\right)

\sf \implies \angle ABD=15.79446612...^{\circ}

Therefore:

\sf \implies \angle ABC=\angle ADB + 38^{\circ}

\sf \implies \angle ABC=15.79446612...^{\circ}+ 38^{\circ}

\sf \implies \angle ABC=54^{\circ}\:\:(nearest\:degree)

<u>Part (b)</u>

Use the tan trig ratio to find angle CAD:

\implies \sf \tan(CAD)=\dfrac{4.9}{7.4}

\implies \sf \angle CAD=\tan^{-1} \left(\dfrac{4.9}{7.4}\right)

\implies \sf \angle CAD=33.5110188...^{\circ}

Therefore:

\sf \implies \angle BAD=13^{\circ}+33.5110188...^{\circ}

\sf \implies \angle BAD=46.5110188...^{\circ}

∠ABC = ∠ABD

Interior angles of a triangle sum to 180°

\sf \implies \angle ABD + \angle BAD + \angle BDA=180^{\circ}

\sf \implies \angle ABC + 46.5110188...^{\circ} + 90^{\circ}=180^{\circ}

\sf \implies \angle ABC=43^{\circ}\:\:(nearest\:degree)

4 0
3 years ago
The triangles are similar.
Gemiola [76]

Answer:

x=12

Step-by-step explanation:

because they are proportional, the side should be 100 so you just solve from that equation for 100.

6 0
3 years ago
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