Round 7897.5 point to the nearest hundredth to the second decimal place

Mathematics

1 answer:

Fynjy0 [20]3 years ago

3 0

Answer:

It looks like this problem is unsolvable, as the decimal only goes to the 10th place.. is there more to the problem?

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IRINA_888 [86]

Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

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Katarina [22]

Answer:

$x=\frac{3}{4} +i\frac{\sqrt{39}}{4}, x=\frac{3}{4} -i\frac{\sqrt{39}}{4}\\$

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Step-by-step explanation:

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3 years ago

Square root of 3x^4 times square root of 5x^2 times square root of 10.

Cloud [144]

Answer:

Step-by-step explanation:

As long as the indices are the same for all the radicals, you can multiply them together. Our index for each of these is 2 (square root) so we multiply them all together and put it under 1 square root sign (radical):

$\sqrt{150x^6$ The largest perfect square in 150 is 25, and the 6th power on the x needs just to be rewritten in terms of an exponent of 2 to give us: