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Yuki888 [10]
3 years ago
12

Round 7897.5 point to the nearest hundredth to the second decimal place

Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

It looks like this problem is unsolvable, as the decimal only goes to the 10th place.. is there more to the problem?

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How do I solve: 15 - w/4 = 28 (this is 2 step equations)
kenny6666 [7]
First we need to isolate the variable so we add 15 to both sides which is
w/4=43  then we need to multiply by 4 to both sides so its 4w=172
then divide by 4 which is 43 so the answer is w=43
8 0
3 years ago
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What is the measure of angle TSU?​
goldfiish [28.3K]

Answer:

80

Step-by-step explanation:

Angle VSU = 100. Angles TSU is a linear pair with angle VSU so adding them together equals 180. 180-100=80.

7 0
3 years ago
Please help i have 1 question. thank you.
liberstina [14]
Since the direction is not specified, it can be safe to assume that the direction of rotation is counterclockwise.

300 degrees is 60 degrees less than 360 degrees, which is a full rotation. Thus, 300 degrees counterclockwise is the same as 60 degrees clockwise.

Note that this shape is a hexagon. Thus, we can divide a hexagon into 6 equilateral triangles, each with measures of 60 degrees. Just move OQ to the adjacent clockwise equilateral triangle and see what it overlaps with.

OQ is the altitude of the equilateral triangle, so our answer will be the altitude of the adjacent clockwise equilateral triangle.

The answer is OF.

6 0
3 years ago
Rationalize the denominator 2√7+√3/3√7-√3​
Dahasolnce [82]

Answer:

\frac{2 \sqrt{7}  + \sqrt{3}}{3 \sqrt{7} -  \sqrt{3}  }  =  \frac{2 \sqrt{7}  + \sqrt{3}}{3 \sqrt{7}  -  \sqrt{3} } . \frac{3 \sqrt{7} +  \sqrt{3}  }{3 \sqrt{7} +  \sqrt{3}  }  \\  \\  =  \frac{(2 \sqrt{7} + 3)(3 \sqrt{7}  +  \sqrt{3})  }{(3 \sqrt{7}  - 3)(3 \sqrt{7} +  \sqrt{3} ) }  \\  \\  =  \frac{(42 + 2 \sqrt{21} + 9 \sqrt{21}   + 3 \sqrt{21} )}{63 - 3}  \\  \\  =  \frac{42 +  2\sqrt{21}  + 9 \sqrt{21} + 3 \sqrt{21}  }{60}

5 0
3 years ago
Read 2 more answers
(Algebra 2)<br><br> Find the inverse of f(x) and its domain.
elixir [45]
Let f(x)=y
f^-1(x)=x
y=1/(x+5) - 1
y+1=1/(x+5)
(x+5)=1/(y+1)
x=1/(y+1)-5
f^-1(x)=1/(x+1) -5

denominator cannot equals to zero
x+1≠0
x≠-1

answer
B
4 0
2 years ago
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