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Yuki888 [10]
3 years ago
12

Round 7897.5 point to the nearest hundredth to the second decimal place

Mathematics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

It looks like this problem is unsolvable, as the decimal only goes to the 10th place.. is there more to the problem?

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What is 60,000,000,000+800.000,000,000=?
Reil [10]

Answer:

130.000,000,000

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
7) In Problem 6 we poured a large and a small bowl of cereal from a box. Suppose the amount of cereal that the manufacturer puts
olga_2 [115]

Question:

The amount of cereal that can be poured into a small bowl varies with a mean of 1.5 ounces and a standard deviation of 0.3 ounces. A large bowl holds a mean of 2.5 ounces with a standard deviation of 0.4 ounces. You open a new box of cereal and pour one large and one small bowl.

Answer:

a) The expected amount of cereal left in the box is 12.2 ounces

b) The standard deviation  \sigma_{x+y+z}, is 0.5099

c) In a Normal model, the probability that the box still contains more than 13 ounces is P(Z-(X+Y) > 13) = 5.821 %.

Step-by-step explanation:

Let X represent the amount of cereal that can be poured into a small bowl and Y represent the amount of cereal that can be poured into a large bowl and Z represent the amount of cereal that the manufacturer puts in the box, then the expected amount of cereal left in the box is given by

Z - (X + Y)

(a) The expected amount of cereal left in the box is given as

P(Z - (X + Y)) = μ = μ_Z - μ_X - μ_Y = 16.2 - 1.5 - 2.5 = 12.2 ounces

The expected amount of cereal left in the box = 12.2 ounces

b) The standard deviation is given by  the root of the sum of the variance

That is

\sigma_{x+y+z} ^2 = \sigma_x^2 + \sigma_y^2 +\sigma_z^2 and

\sqrt{\sigma_{x+y+z} ^2}  = \sqrt{\sigma_x^2 + \sigma_y^2 +\sigma_z^2} =\sqrt{0.1^2+0.4^2+0.3^2} = 0.5099

The standard deviation,  \sigma_{x+y+z}, = 0.5099

c) The probability that the box still contains more than 13 ounces is given by

P(Z-(X+Y) > 13)

Where z-score is  

z=\frac{x-\mu}{\sigma} = \frac{13-12.2}{0.5099}=  1.5689 ≈ 1.57

From the z-score table P(Z = 1.57) = 0.94179

Therefore the probability of the box containing ≤ 13 is 0.94179, that is

P(Z-(X+Y) ≤ 13) = 0.94179 and

P(Z-(X+Y) > 13) = 1 - 0.94179 = 0.05821 = 5.821 %.

3 0
3 years ago
Need help with the last 2 numbers ​
professor190 [17]

Answer:

the solution is t ≤1 (1)

6 0
3 years ago
Attend to precision. Mimi says that the 16 is 4.<br> Is Mimi correct? Explain.
garri49 [273]

Answer: It depends on the terms.

Step-by-step explanation: In fraction terms 16 is equivalent to 4. In number terms 16 is a number larger than 4.

8 0
3 years ago
Which vectors represent the reflection of the vector &lt;3, -7&gt; across the x-axis? A. [3/7} B. [-3/7] C. &lt;-3, 7&gt; D. &lt
Alexandra [31]

Answer:

D)    < 3, 7)>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given that the vector < 3 , -7 >

Given the vector reflection across the x-axis

                   (x,y) → (x , -y)

The vector < 3,-7> →< 3, -(-7)>

                  < 3,-7> →< 3, 7)>

3 0
3 years ago
Read 2 more answers
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