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Talja [164]
3 years ago
13

Solve each absolute value equation or inequality and choose the correct answer from the choices provided

Mathematics
1 answer:
NeX [460]3 years ago
7 0

<u>Answers:</u>


1) |x|+5=18  

If we want to solve equations with absolute values we must know we have to find the solution for both positive and negative values. This is because positive and negative values have a positive absolute value.

In a mathematical form this is:

<h2>For any positive number a, the solution to |x|=a is: </h2><h2>|x|=a or |x|=-a </h2>

In this case we have to clear |x| first:

|x|=18-5

|x|=13

This means x=13 or x=-13

Therefore, the answer is B

2) |x+3|

In the case of inequalities we have the following statement:  

<h2>For any positive value of a: </h2><h2>|x| is equivalent to -a </h2><h2>|x|>a is equivalent to x or x>a </h2>

Where x may be a normal variable or an algebraic expression, as the expression in this exercise.

According to the explained above:

 

|x+3| is equivalent to -5< x+3

This means we have to solve the inequality for both cases.

<u> Case 1: </u>

x+3

x

x

<u>Case 2: </u>

x+3>-5

x>-5-3

x>-8

Then, x or x>-8

3) |-3n|-2=4

|-3n|=4+2

|-3n|=6

This means |-3n|=6 or |-3n|=-6

<u>Case 1: </u>

-3n=6

n=-\frac{6}{3}

n=-2

<u>Case 2: </u>

-3n=-6

n=\frac{-6}{-3}

n=2

Then, the answer is A: n=-2 or n=2


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alexgriva [62]

Answer:

The probability of using one or the other is 36%

Step-by-step explanation:

For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:

Probability of passing Professor Jones math class = 64% =0,64

P(J) = 0.64

Probabiliry of passing Professor Smith's physics class = 32% =0.32

P(S) = 0.32

Probability of passing both is = 30% = 0.30

P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram

We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing  Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:

P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%

If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.

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3 years ago
Jenny bought gas for her car gas cost 3.45 pee gallon jenny bought 12.2 gallons what was the total cost for jennys gas
Semenov [28]

Answer:

$42.09

Step-by-step explanation:

1. multiply the cost per gallon (3.45) by the gallons purchased (12.2)

    3.45*12.2 = 42.09

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