2) When Janet put her marble collection in groups of 7 there were two marbles left over, when she put them in groups of 5 there
were 3 marbles left over. What is the fewest number of marbles that Janet could have had in her collection?
1 answer:
Answer:
23 marbles
Step-by-step explanation:
3 groups of 7 = 21 +2 = 23
4 groups of 5 = 20 +3 = 23
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the answer would be 8.
2 times 8 = 16 minus 5 = 11
The missing fraction is 13/100
Answer:The expression can be simplified in following steps;
Step-by-step explanation:
(16+a)+15=0
16+15+a=0
31+a=0
a=-31
When doing that it will be B
Answer:
Step-by-step explanation:
