I need to find X x^2 = 28

Find the equation perpendicular to the line y=−3x+5 that passes through point (2, 6).

ololo11 [35]

Hey there! :)

Perpendicular to y = -3x + 5 ; passes through (2, 6).

Our slope is -3. We know this because it is in the "m" position from slope-intercept form. However, since our equation we're looking for is perpendicular to our given one, we must find the negative reciprocal of -3.

A negative reciprocal is simply a number that is flipped and either given a negative or gets a negative removed.

So the negative reciprocal of -3 is 1/3. This means that our new slope is 1/3.

Now, using point-slope form ( y-y₁=m(x-x₁) ), our new slope (1/3) & (2, 6) , let's find our new equation!

y-y₁=m(x-x₁) y - (6) = 1/3(x - 2)

Simplify.

y - 6 = 1/3x - 2/3

~Hope I helped!~

5 0

4 years ago

Read 2 more answers

What is the formula for the volume of a sphere?

Vikki [24]

Answer:

D,

Step-by-step explanation:

the volume of a sphere is 4/3πr^3

7 0

3 years ago

Please help meeeeeeeeeeeeeeeeeeeeeeeeeeeee

natulia [17]

Answer:

77 m (nearest metre)

Step-by-step explanation:

Angle of Elevation

If a person stands at a point and looks up at an object, the angle between their horizontal line of sight and the object is called the angle of elevation.

To find how tall the flagpole is, model as a right triangle and solve using the tan trigonometric ratio.

Tan trigonometric ratio

$\sf \\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle

Given information:

Person height = 1.6 m
Horizontal distance (from person to flagpole) = 35 m
Angle of elevation = 65°

Therefore:

$\theta$ = 65°
O = height of flagpole less height of person
A = 35 m

As the person is 1.6 m tall, we model the line of sight as 1.6 m above ground level. Therefore, when calculating the height of the flagpole, we will need to add the height of the person to the value found using the trig ratio.

Substitute the given values into the formula and solve for O:

$\implies \sf \tan(65^{\circ})=\dfrac{O}{35}$