Answer:
He has 151 pages left in his book
Step-by-step explanation:
Saturday
1 hr = 38 pg
3.5 x 38 = 133
Sunday
1 hr = 44 pg
3.5 x 44 = 154
pages read
133 + 154 = 287
starting amount 438
438 - 287 = 151
Step-by-step explanation:
In,
Question 2 I have already answered,
Q. 3)
<h3>
<em><u>Given</u></em><em><u> </u></em><em><u>Question</u></em><em><u>:</u></em></h3>
<em><u>Given</u></em><em><u> </u></em><em><u>values</u></em><em><u>:</u></em><em><u>-</u></em>
c = 6 , d = 3
<em><u>By</u></em><em><u> </u></em><em><u>putting</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>values</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>question</u></em><em><u>, </u></em>
= <em><u>12 (Ans)</u></em>
Answer:
I would use addition
Step-by-step explanation:
Since addition is the opposite of subtraction.
Answer:
523 -61= 462
456-187=269
Step-by-step explanation:
subtract the last numbers first 3-1 which is 2 then 2-6 which is impossible so you borrow from 5 and add 10 to 2 which become 12-6 which is 6 the the first number has only 4 left because you borrowed from it which is 4 so 523-61= 462.
subtract the last number 6-7 it not possible because 6 is less than 7 so borrow from 5 then add 10 to 6 which become 16-7=9 then the second number you have 4-8 since you borrowed from 5, 4-8 is also not possible so borrow from 4 which become 14-8 which is 6 and the first number which is now 3- 1 which is 2 so all the result become 269
Please, post the instructions along with your question, and if possible share the question in symbolic form, not in words.
Do you mean Question #5? By (2) x cube, do you mean 2x^3?
I strongly suggest that you use lots of parentheses ( ) to show how your numbers are grouped, and not to use " x " to denote multiplication (use " * " for that, please.
If only you'll clear this up, I'd be happy to help.
I will assume that your post is 2x^3 - 3(9x-5)^2.
Then 2x^3 - 3(81x - 90x + 25). Does this have any resemblance to what you wanted me to see in your post?
