the correct question is
What values of b satisfy 3(2b+3)^2 = 36
we have
Divide both sides by 
take the square root of both sides
therefore
the answer is
the values of b are
y = x³ + 3x² - x - 3
0 = x³ + 3x² - x - 3
0 = x²(x) + x²(3) - 1(x) - 1(3)
0 = x²(x + 3) - 1(x + 3)
0 = (x² - 1)(x + 3)
0 = (x² + x - x - 1)(x + 3)
0 = (x(x) + x(1) - 1(x) - 1(1))(x + 3)
0 = (x(x + 1) - 1(x + 1))(x + 3)
0 = (x - 1)(x + 1)(x + 3)
0 = x - 1 or 0 = x + 1 or 0 = x + 3
+ 1 + 1 - 1 - 1 - 3 - 3
1 = x or -1 = x or -3 = x
Solution Set: {-3, -1, 1}
(-5a)(-3a ²)
=
15a³
-5 x -3 = 15 ( negative times negative = positive)
a x a² = a³ ( when multiplying exponents, you add the exponents together )
What happens to the number after the subtraction sign in each problem
It would go to the opposite side
