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kkurt [141]
3 years ago
8

Which of the following equations shows the correct form of the equation x 2 + 10x + 25 = 16 if the zero product property is to b

e used?
Mathematics
1 answer:
-Dominant- [34]3 years ago
7 0
Yes that is the correct answer the first one
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evaluate the expression 9(a 2b) c for a = –3, b = –2, and c = 1. i kept getting the answer of 10 but it's not one of my choices
den301095 [7]
What grade are u? I'm just asking cause the formulas are going with grade I could help if u want me too
7 0
3 years ago
Help 10 POINTS MATH IS NOT MY STRONG SUIT
Masja [62]

Answer:

infinite number of solutions

Step-by-step explanation:

Work with the second equation.  Subtract 8x from both sides.

- 4y + 8x - 8x = -8x - 12                   Collect like terms.

-4y = - 8x - 12                                   Divide by - 4

-4y/-4 = - 8x/-4 - 12/-4

y = 2x + 3

That is exactly the same line as the first given.  There is an infinite number of solutions.

6 0
2 years ago
What are the zeros of the graphed function y = (x + 3)(x + 5)?
tensa zangetsu [6.8K]
Y=(x+3)(x+5)
0=(x+3)(x+5)
0=x+3
Subtract three on both sides
-3=x
0=x+5
Subtract five on both sides
-5=x
So, -3 and -5 are the zeros of the graphed function.
Hope I helped!
5 0
2 years ago
Read 2 more answers
C
Rama09 [41]

Answer:

  • m∠AOB=139°

Step-by-step explanation:

m∠AOB+m∠BOC=180°

m∠AOB=8x+51°

m∠BOC=6x-25°

~

\tt 8x+51+6x-25=180

\tt 14x+26=180

\tt 14x=180-26

\tt \cfrac{14x}{14} =\cfrac{154}{14}

\tt x=11

m∠AOB:-

\tt 8(11)+51

\tt =88+51

\tt =139^{o}

Therefore, m∠AOB=139°

7 0
2 years ago
Please help me out! It’s urgent!
LuckyWell [14K]

Answer:

8 square units

Step-by-step explanation:

Area of the shaded shape = sum of shaded squares × 1 square unit

= 8 × 1 = 8 square units

6 0
2 years ago
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