1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
devlian [24]
2 years ago
10

What are the zeros of the graphed function y = (x + 3)(x + 5)?

Mathematics
2 answers:
Gelneren [198K]2 years ago
7 0

-5 and -3 will be your answer, I just took the test.

tensa zangetsu [6.8K]2 years ago
5 0
Y=(x+3)(x+5)
0=(x+3)(x+5)
0=x+3
Subtract three on both sides
-3=x
0=x+5
Subtract five on both sides
-5=x
So, -3 and -5 are the zeros of the graphed function.
Hope I helped!
You might be interested in
<img src="https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Cunderline%7B%20%5Ctext%7Bquestion%7D%7D%7D%20%3A%20" id="TexFormula1"
Inga [223]

Answer:

y=-\sqrt{3}x+2

Step-by-step explanation:

We want to find the equation of a straight line that cuts off an intercept of 2 from the y-axis, and whose perpendicular distance from the origin is 1.

We will let Point M be (x, y). As we know, Point R will be (0, 2) and Point O (the origin) will be (0, 0).

First, we can use the distance formula to determine values for M. The distance formula is given by:

\displaystyle d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Since we know that the distance between O and M is 1, d=1.

And we will let M(x, y) be (x₂, y₂) and O(0, 0) be (x₁, y₁). So:

\displaystyle 1=\sqrt{(x-0)^2+(y-0)^2}

Simplify:

1=\sqrt{x^2+y^2}

We can solve for y. Square both sides:

1=x^2+y^2

Rearranging gives:

y^2=1-x^2

Take the square root of both sides. Since M is in the first quadrant, we only need to worry about the positive case. Therefore:

y=\sqrt{1-x^2}

So, Point M is now given by (we substitute the above equation for y):

M(x,\sqrt{1-x^2})

We know that Segment OM is perpendicular to Line RM.

Therefore, their <em>slopes will be negative reciprocals</em> of each other.

So, let’s find the slope of each segment/line. We will use the slope formula given by:

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Segment OM:

For OM, we have two points: O(0, 0) and M(x, √(1-x²)). So, the slope will be:

\displaystyle m_{OM}=\frac{\sqrt{1-x^2}-0}{x-0}=\frac{\sqrt{1-x^2}}{x}

Line RM:

For RM, we have the two points R(0, 2) and M(x, √(1-x²)). So, the slope will be:

\displaystyle m_{RM}=\frac{\sqrt{1-x^2}-2}{x-0}=\frac{\sqrt{1-x^2}-2}{x}

Since their slopes are negative reciprocals of each other, this means that:

m_{OM}=-(m_{RM})^{-1}

Substitute:

\displaystyle \frac{\sqrt{1-x^2}}{x}=-\Big(\frac{\sqrt{1-x^2}-2}{x}\Big)^{-1}

Now, we can solve for x. Simplify:

\displaystyle \frac{\sqrt{1-x^2}}{x}=\frac{x}{2-\sqrt{1-x^2}}

Cross-multiply:

x(x)=\sqrt{1-x^2}(2-\sqrt{1-x^2})

Distribute:

x^2=2\sqrt{1-x^2}-(\sqrt{1-x^2})^2

Simplify:

x^2=2\sqrt{1-x^2}-(1-x^2)

Distribute:

x^2=2\sqrt{1-x^2}-1+x^2

So:

0=2\sqrt{1-x^2}-1

Adding 1 and then dividing by 2 yields:

\displaystyle \frac{1}{2}=\sqrt{1-x^2}

Then:

\displaystyle \frac{1}{4}=1-x^2

Therefore, the value of x is:

\displaystyle \begin{aligned}\frac{1}{4}-1&=-x^2\\-\frac{3}{4}&=-x^2\\ \frac{3}{4}&=x^2\\ \frac{\sqrt{3}}{2}&=x\end{aligned}

Then, Point M will be:

\begin{aligned} \displaystyle M(x,\sqrt{1-x^2})&=M(\frac{\sqrt{3}}{2}, \sqrt{1-\Big(\frac{\sqrt{3}}{2}\Big)^2)}\\M&=(\frac{\sqrt3}{2},\frac{1}{2})\end{aligned}

Therefore, the slope of Line RM will be:

\displaystyle \begin{aligned}m_{RM}&=\frac{\frac{1}{2}-2}{\frac{\sqrt{3}}{2}-0} \\ &=\frac{\frac{-3}{2}}{\frac{\sqrt{3}}{2}}\\&=-\frac{3}{\sqrt3}\\&=-\sqrt3\end{aligned}

And since we know that R is (0, 2), R is the y-intercept of RM. Then, using the slope-intercept form:

y=mx+b

We can see that the equation of Line RM is:

y=-\sqrt{3}x+2

6 0
3 years ago
Read 2 more answers
Use the graph to determine the domain and range of the relation, and whether the relation is a function
ohaa [14]
The answer is C. The domain is all points between -8 and 8 since it keeps waving back and forth. The range is all real numbers the graph continues on forever. And it is not a function because it does not pass the vertical line test
6 0
3 years ago
Mrs.Browns rectangular kitchen is 10 ft wide and.16 ft long, if she creates a scale drawing.With a length of 4 inches, what woul
Nataliya [291]

Answer:

2.5 inches

Step-by-step explanation:

1 feet = 12 inches

The length is 16 ft x 12 = 192 inches

The length was scales by an unknown measure which i would represent with x . The equation is as follows

192 inches x a = 4 feet

a = 48

The kitchen was scaled by 48

10 x 12 = 120 inches

120/48 = 2.5 inches

7 0
2 years ago
Simple math help?<br> Solve for x<br> √x+12 = √x+2
lozanna [386]
This is an impossible equation. If sqrt(x) = sqrt(x), and sqrt(x) + 2 = sqrt(x) + 12, then that would mean that 2=12, which is incorrect.
3 0
2 years ago
Which of the following rules describes the function graphed below?
n200080 [17]

Answer:

D

Step-by-step explanation:

Output = 3*input - 2. Observe the graph again

4 0
2 years ago
Other questions:
  • Which could be the resulting equation when elimination is used to solve the given system of equations?
    11·1 answer
  • Solve x²+5x+6=0 by completing the square​
    5·1 answer
  • What is the range of the graph?
    8·2 answers
  • When y varies directly with x, if y = 9 and x = 8 find y when x = 16
    8·1 answer
  • 6000 written as a whole number multiplied by a power of 10
    15·2 answers
  • How to do probability?
    8·1 answer
  • If y varies inversely with x, and y = -16 when x = -64, what is the constant of variation?
    15·2 answers
  • Ms. Garza is an architect who is helping with the set design for a school play. She was asked to cover the figure on the left wi
    10·2 answers
  • Please help me with this one please ​
    10·2 answers
  • In the figure below lines m and n are parallel. in the diagram shown, Angle 7 measures 92 degrees. What is the measure of Angle
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!