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serious [3.7K]
2 years ago
13

20 points! write a 100-150 word annotated bibliography using this source: https://go.gale.com/ps/retrieve.do?tabID=Reference&amp

;resultListType=RESULT_LIST&searchResultsType=MultiTab&searchType=BasicSearchForm&currentPosition=3&docId=GALE%7CCX3045302067&docType=Topic+overview&sort=Relevance&contentSegment=ZXAP-VRL&prodId=SUIC&contentSet=GALE%7CCX3045302067&searchId=R3&userGroupName=nap4157&inPS=true
Advanced Placement (AP)
1 answer:
Svetllana [295]2 years ago
3 0
It says I need a login password
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Explain your reasoning in words or by drawing. 1/3=4/12
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As you can see both drawings take up the same amount of surface area and the same amount of surface area is colored. The one on the right has 12 spaces, while the one on the left only has 3.

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What condition results in magma cooling and forming a “glassy” igneous rock?
Gennadij [26K]

Answer: C)  extremely rapid cooling

Explanation:

When magma goes through extremely rapid cooling and especially if it did not dissolve enough water into it, it could freeze to glass or the mineral crystals that will be formed will be so small, they will look like glass.

This is because the reactions that occur to create minerals are affected directly by temperature such that if the magma cools down extremely slowly, it will form very large crystals but extremely fast would result in small crystals.

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3 years ago
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Explain in detail, how you solved the following problem: The first two terms of a sequence are 10 and 20. If each term after the
KIM [24]

Answer:

T_{2020} = 15

Explanation:

Given

T_1 = 10

T_2 = 20

Each term after the second term is the average of all of the preceding terms

Required:

Explain how to solve the 2020th term

Solve the 2020th term

Solving the 2020th term of a sequence using conventional method may be a little bit difficult but in questions like this, it's not.

The very first thing to do is to solve for the third term;

The value of the third term is the value of every other term after the second term of the sequence; So, what I'll do is that I'll assign the value of the third term to the 2020th term

<em>This is proved as follows;</em>

From the question, we have that "..... each term after the second term is the average of all of the preceding terms", in other words the MEAN

T_{n} = \frac{\sum T{k}}{n-1} ; where: k = 1 .... n -1

<em>Assume n = 3</em>

T_{3} = \frac{T_1 + T_2}{2}

<em>Multiply both sides by 2</em>

2 * T_{3} = \frac{T_1 + T_2}{2} * 2

2T_{3} = T_1 + T_2

<em>Assume n = 4</em>

T_{4} = \frac{T_1 + T_2 + T_3}{3}

T_{4} = \frac{(T_1 + T_2) + T_3}{3}

Substitute 2T_{3} = T_1 + T_2

T_{4} = \frac{2T_3 + T_3}{3}

T_{4} = \frac{3T_3}{3}

T_{4} = T_3

Assume n = 5

T_{5} = \frac{T_1 + T_2 + T_3 +T_4}{4}

T_{5} = \frac{(T_1 + T_2) + T_3 +(T_4)}{4}

Substitute 2T_{3} = T_1 + T_2 and T_{4} = T_3

T_{5} = \frac{2T_3 + T_3 +T_3}{4}

T_{5} = \frac{4T_3}{4}

T_{5} = \frac{(5-1)T_3}{5-1}

<em>Replace 5 with n</em>

T_{n} = \frac{(n-1)T_3}{n-1}

<em>(n-1) will definitely cancel out (n-1); So, we're left with</em>

T_{n} = T_3

Hence,

T_{2020} = T_3

Calculating T_3

T_{3} = \frac{10 + 20}{2}

T_{3} = \frac{30}{2}

T_{3} = 15

Recall that T_{2020} = T_3

T_{2020} = 15

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