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Helen [10]
3 years ago
11

At the Dessert Island Pastry Cafe, there are 2 cakes for every 7 donuts and 11 brownies for every 3 cakes. What is the ratio of

brownies to donuts? Write your answer as a simplified fraction.
Mathematics
2 answers:
Westkost [7]3 years ago
7 0

Answer: 22/21

Step-by-step explanation:

2 cakes : 7 donuts      →   6 cakes : 21 donuts

3 cakes : 11 brownies  →  6 cakes : 22 brownies

22 brownies : 21 donuts

Now, simply write this as a fraction. 22/21

lukranit [14]3 years ago
7 0

Answer:

22/21............

............

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Step-by-step explanation:

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3 years ago
I need to increase my sales by 35% in order to meet my goal for the month. you have 45 Sales and need?
Anastasy [175]
45 + 0.35(45)
We can make it simpler:
1.35(45)
60.75
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5 0
3 years ago
Read 2 more answers
What is the product of 5 + 2i and 7 + 3i?
ale4655 [162]
The answer is (4) because you multiply the like terms in the equation. 5*7=35 and 3i*2i=6i.

Answer is (4)
4 0
3 years ago
Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x)= 6x^1/3 + 3x^4/3. You must justify
irina [24]

Answer:

x-coordinates of relative extrema = \frac{-1}{2}

x-coordinates of the inflexion points are 0, 1

Step-by-step explanation:

f(x)=6x^{\frac{1}{3}}+3x^{\frac{4}{3}}

Differentiate with respect to x

f'(x)=6\left ( \frac{1}{3} \right )x^{\frac{-2}{3}}+3\left ( \frac{4}{3} \right )x^{\frac{1}{3}}=\frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}

f'(x)=0\Rightarrow \frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}=0\Rightarrow x=\frac{-1}{2}

Differentiate f'(x) with respect to x

f''(x)=2\left ( \frac{-2}{3} \right )x^{\frac{-5}{3}}+\frac{4}{3}x^{\frac{-2}{3}}=\frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}\\f''(x)=0\Rightarrow \frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}=0\Rightarrow x=1

At x = \frac{-1}{2},

f''\left ( \frac{-1}{2} \right )=\frac{4\left ( -1+4\left ( \frac{-1}{2} \right ) \right )}{3\left ( \frac{-1}{2} \right )^{\frac{5}{3}}}>0

We know that if f''(a)>0 then x = a is a point of minima.

So, x=\frac{-1}{2} is a point of minima.

For inflexion points:

Inflexion points are the points at which f''(x) = 0 or f''(x) is not defined.

So, x-coordinates of the inflexion points are 0, 1

7 0
3 years ago
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yaroslaw [1]

Answer:

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