I don’t know how to solve this

Mathematics

1 answer:

V125BC [204]3 years ago

7 0

Assuming that both triangles are an exact copy of one another, it is safe to assume that 3y-7 is equal to 41. Set up an equation

3y-7=41

Add 7 to both sides

3y=48

Divide both sides by 3

y=16

Now to find PN.

Based on what we know, we can assume that MP = PN. Let's make some equations!

MP = 17x-8 PN = 11x+4

17x-8 = 11x+4

Subtract 11x from both sides

6x-8 = 4

Add 8 to both sides

6x = 12

Divide by 2

x=2

Substitute 2 in for x in the equation for PN

11(2)+4

Multiply 11 by 2

22+4 = 26

PN = 26

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<em>x equals 22</em>

<h2>Explanation:</h2>

____________________________________________

The Segment Postulate states the following:

<em>Given two end points A and B, a third point C lines on the segment AB if and only if the distances between the points satisfy the equation:</em>

$\overline{AB}=\overline{AC}+\overline{CB}$

____________________________________________

From the figure:

$\overline{AC}=8+x \\ \\ \overline{CB}=10 \\ \\ \overline{AB}=40$

Our goal is to find x:

$\overline{AB}=\overline{AC}+\overline{CB} \\ \\ Substituting \ values: \\ \\ 40=(8+x)+10 \\ \\ 18+x=40 \\ \\ Subtracting \ 18 \ from \ both \ sides: \\ \\ 18-18+x=40-18 \\ \\ \boxed{x=22}$