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agasfer [191]
4 years ago
14

What is the average speed in kilometers per hour if you travel 194 kilometers in 4.1 hours?

Mathematics
1 answer:
Tanya [424]4 years ago
8 0
47.317 or about 47.32kph is the average speed.

You could set this up as a standard ratio to help visualize how to solve this problem. For every 194 kilometers, 4.1 hours has passed in meaning the ratio would be 194:4.1. Next find what side would make 4.1 would change into 1 so you would do 4.1 divided by 4.1 which will give you 194:1. But with a ratio you need to divide on both sides of the ratio. So do 194/4.1 which would equal to about 47.317.
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The midpoint of K is M(-3, -1). One endpoint is J(-12, -11). What are the coordinates of endpoint K?
Over [174]

Answer: 2 times sqrt(181) (approximately 26.9)

Step-by-step explanation:

First, we can plot these points on a graph. Then, we’ll use the Distance Formula to calculate the distance between the two points, which is sqrt(181).


Since the problem tells us that one of our coordinates is the midpoint of K, we know that the length of the segment we just calculated is 1/2 of K. We can multiply our answer to get that K is 2 times sqrt(181).

7 0
2 years ago
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A coin is tossed and a die is rollled find the probability of getting a head and a number greater then 2
NemiM [27]
Let's find both of the probabilities and multiply them.
First, we know that the theoretical P(Getting Heads) is 1/2, because there's two sides to a penny.
Next, we know that a dice has 6 sides, so P(Rolling a number greater than 2) is going to be 4/6, or 2/3.
Let's multiply our probabilities.
We have:
1/2 × 2/3, which get's us 2/6, or 1/3.
P(Flipping heads and rolling greater than 2) = 1/3.
Hope this helped!
8 0
4 years ago
Find the slope of each line.
Lelechka [254]

Answer:

-1/2

Step-by-step explanation:

5 0
3 years ago
I don't understand how to the problem
Amanda [17]

We have:

(30x²+23x+16)/(cx+3) - 13/(cx+3) = 6x+1

(30x²+23x+16 - 13)/(cx+3) = 6x+1

(30x²+23x+3)/(cx+3) = 6x+1

30x²+23x+3 = (cx+3)(6x+1)

30x²+23x+3 = 6cx²+cx+18x+3

30x² + 23x + 3 - 6cx² - cx - 18x - 3 = 0

(30 - 6c)x² +(5 - c)x = 0

6(5 - c)x² +(5 - c)x  = 0

(5 - c)(6x² +x) = 0, and x∈ R\ {3/c} ⇒ 5 - c = 0 ⇒ c = 5.

 

6 0
3 years ago
Y = 3x +1; domain = {-1, 0, 1}<br> HELP PLEASE
ser-zykov [4K]

We have to put values of domain to find range

\\ \ast\sf\longmapsto y=3x+1

\\ \ast\sf\longmapsto D_R=[-1,0,1]

\\ \ast\sf\longmapsto y=3(-1)+1=-3+1=-2

\\ \ast\sf\longmapsto y=3(0)+1=0+1=1

\\ \ast\sf\longmapsto y=3(4)+1=12+1=13

Now

\\ \ast\sf\longmapsto R_R=[-2,1,13]

6 0
3 years ago
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