Answer:
Step-by-step explanation:
H1 = Hit rate of level 1 cache = 0.95
T1 = Access time for level 1 cache = 1
H2 = Hit rate of level 2 cache = 0.8
T2 = Access time for level 2 cache = 3
Hm = Hit rate of Main Memory = 1
Tm = Access time for Main Memory = 80
Average access time = [H1*T1]+[(1-H1)*H2*T2]+[(1-H1)(1-H2)*Hm*Tm]
= [0.95*1]+[1-0.95]*0.8*3]+[(1-0.95)(1-0.8)*1*80]
= [0.95+0.05*0.8*3]+[0.05*0.2*1.80]
= 2.4+0.018 = 2.418
Average access time = 2.418
I THINK the answer is 6000 square feet because each one is 6 square feet and you have 1000 of them so 6 square feet times 1000 squares is 6000 square feet.
Answer:
There is no valid value for b
Step-by-step explanation:
We solve the above question using the law of cosines
b² = a² + c² - 2ac × Cos B
B = 42°, a = 6, c = 4
b² = 6² + 4² - 2 × 6 × 4 × Cos 42
b =√6² + 4² - 2 × 6 × 4 × Cos 42
b = √36 + 16 - 48 × Cos 42
Solving the above question, there is no valid value for b
Answer:
Step-by-step explanation:
Let m represent the number of miles that she drives per day.
She works 5 days per week. This means that the total number of miles that she drives in a week would be
5 × m = 5m
Ms.Franks drives a maximum of 150 miles per week to and from work. Therefore, the inequality that shows m the number of miles she drives per day would be
5m ≤ 150
m ≤ 150/5
m ≤ 30
