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Jet001 [13]
3 years ago
13

How do you get this to its Standard Form?And is it linear?

Mathematics
2 answers:
iren [92.7K]3 years ago
7 0

x/2 = (y+3) /6

using cross products

6* x = 2 * (y+3)

distribute

6x = 2y+6

subtract  2y from each side

6x -2y = 6


we can simplify this by dividing each term by 2

3x - y = 3

this is the standard form of a line (Ax + By =C)

this is linear because x and y are only to the first power)

Alchen [17]3 years ago
4 0

let's bear in mind that

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient


so, let's do away with the denominators by multiplying both sides by the LCD of all fractions, in this case 6.


\bf \cfrac{x}{2}=\cfrac{y+3}{6}\implies\stackrel{\textit{multiplying by }\stackrel{LCD}{6}}{6\left( \cfrac{x}{2} \right)=6\left( \cfrac{y+3}{6} \right)}\implies 3x=y+3\implies \stackrel{\textit{standard form}}{3x-y=3}

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