6(3-y) Simplified please help Me
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Answer:
Yes, there is evidence to support that claim that instructor 1 is more effective than instructor 2
Step-by-step explanation:
We can conduct a hypothesis test for the difference of 2 proportions. If there is no difference in instructor quality, then the difference in proportions will be zero. That makes the null hypothesis
H0: p1 - p2 = 0
The question is asking whether instructor 1 is more effective, so if he is, his proportion will be larger than instructor 2, so the difference would result in a positive number. This makes the alternate hypothesis
Ha: p1 - p2 > 0
This is a right tailed test (the > or < sign always point to the critical region like an arrowhead)
We will use a significance level of 95% to conduct our test. This makes the critical values for our test statistic: z > 1.645.
If our test statistic falls in this region, we will reject the null hypothesis.
<u>See the attached photo for the hypothesis test and conclusion</u>
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