A)
Given: dr/dt = .03 m/s and r = 18 m
Volume of a sphere = (4/3)*PI*r^3
Take the derivative of both sides, so
dv/dt = 4*PI*r^2*dr/dt
Plug in the givens and you have the rate of increase of the volume
B)
Given: V = 288 m^3 and I'm going to assume that r and dr/dt are the same as in part A
Surface Area = 4*PI*r^2
Take the derivative on both sides, so
dA/dt = 8*PI*r*dr/dt
Again, plug in the givens and you'll have the rate of increase in the surface area
C)
This part, it's been awhile since I've done related rates, so it may take me awhile, but perhaps the next person can answer it before I finish.
We have to find the volume of oblique cone. An oblique cone is a special type of cone in which the apex is not located directly above the center of the circular base, so it looks like a slanted cone.
Volume of oblique cone = 
where 'r' is the radius and 'h' is the height.
Here r = 6 cm and h = 10 cm
Volume = 
= 
= 
So, the volume of the given oblique cone is
.
Option 4 is the correct answer.
The square root of 30 in its simplest form is 5.5 ( I think)
Answer:
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If they are independent, then P(A and B) is just P(A) times P(B). Which is 0.5*0.2=0.1