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Nataliya [291]
4 years ago
7

What phrase can you remember to easily determine the ratio for each trigonometric function

Mathematics
1 answer:
Anna11 [10]4 years ago
3 0
Soh cah toa
Soh is Sin= opposite and hypotenuse
Cah is cos= adjacent and hypotenuse
Toa is tan= opposite and adjacent
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6/5<br><br> 36/25<br> Find the 10th term.
harina [27]

Answer:

36/25=1 and 11/25  6/5=1 and 1/5

Step-by-step explanation:

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5 0
3 years ago
Help Me!!!
Zigmanuir [339]
I'll just help quickly with a couple of expressions that are equivalent.
3(m+5+9m)
If you solve it out, you get 3m+15+27m.
Simply the expression to get 30m+15.
You can regroup to make another expression 5(6m+3) which is also equal.
7 0
3 years ago
A representative from each of seven nations is to sit at a round table to discuss trade relations. How many ways can the represe
Sidana [21]
The correct answer is 720. Just turned it in and got a 100. Good luck and hoped this help ya.
7 0
3 years ago
Read 2 more answers
Un edificio proyecta una sombra de 7.5m.mientras que un arbol que mide 1.6 m de altura proyecta una sombra 1.85 M¿Cual es la alt
sattari [20]

Answer: The height of the building is 6.49 meters.

Step-by-step explanation:

This can be translated to:

"A building projects a 7.5 m shadow, while a tree with a height of 1.6 m projects a shadow of 1.85 m.

Which is the height of the building?"

We can conclude that the ratio between the projected shadow is and the actual height is constant for both objects, this means that if H is the height of the building, we need to have:

(height of the building)/(shadow of the building) = (height of the tree)/(shadow of the tree)

H/7.5m = 1.6m/1.85m

H = (1.6m/1.85m)*7.5m = 6.49m

The height of the building is 6.49 meters.

5 0
3 years ago
A submarine dives 300 feet every 2 minutes, and 6,750 feet every 45 minutes. Solve for A and
Gelneren [198K]
A: To find the rate in feet per minute, we can use the information given. 
Every two minutes, the submarine dives 300 feet. So 
\frac{300feet}{2minutes} = 150 \frac{feet}{minute} .
In order to confirm that our rate is correct, we can use the second set of information given.
\frac{6750feet}{45minutes}=150 \frac{feet}{minute}.
Since we know that the rate is 150 feet per minute, we can multiply it by any number of minutes and get the answer of how deep the submarine is. We can use a variable x to represent the number of minutes and y to represent the depth in feet.
y=150x
There's our equation.
B: It would be more reasonable to use an equation with the rate feet per minute because it is more accurate since the time interval isn't too big.
3 0
3 years ago
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