Question

Find two consecutive positive integers such that the sum of their squares is 145

Answer 1

Answer:

8,9

Step-by-step explanation:

(x)^2+(x+1)^2=145

x²+x²+2x+1=145

2x²+2x+1-145=0

x²+x-72=0

x²+9x-8x-72=0

x(x+9)-8(x+9)=0

(x+9)(x-8)=0

x=-9(rejected being negative)

x=8

x+1=8+1=9