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3 years ago

Find two consecutive positive integers such that the sum of their squares is 145

Mathematics

1 answer:

DerKrebs [107]3 years ago

7 0

Answer:

8,9

Step-by-step explanation:

(x)^2+(x+1)^2=145

x²+x²+2x+1=145

2x²+2x+1-145=0

x²+x-72=0

x²+9x-8x-72=0

x(x+9)-8(x+9)=0

(x+9)(x-8)=0

x=-9(rejected being negative)

x=8

x+1=8+1=9

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Step-by-step explanation:

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REMEMBER PEMDAS

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Hope this helps have a wonderful evening!

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