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3 years ago

8

Jean noticed that the tar pit bubbled more on warm days than on cool days or at night. Is the air temperature the dependent vari

able or the independent variable?
A. Independent
B. Dependent

1 answer:

andreev551 [17]3 years ago

6 0

It's indepentent. In fact, the tar pit's temperature DEPENDS (dependent variable) by the air's temperature (independent variable).

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I need help i dont know the answers

Arlecino [84]

Answer: Change the number: 36

To:48

Step-by-step explanation:

12x2 is 24 but 24 x 2 isn’t 36

5 0

3 years ago

Reduce To Simplest Form.<br><br>2/2 + 1.75 - 44/25 =

Soloha48 [4]

Answer/Step-by-step explanation:

First, we should make each fraction, decimal, whole number into fraction and number form.

So, 2/2 = 1.

1.75 is 1 3/4.

44/25 is 1 19/25.

Now we have our equation, now we can do this equation easier.

1 + 1 3/4 - 1 19/25.

1 + 1 3/4 = 2 3/4.

Then, we turn both numbers to Decimal Form.

2 3/4 = 2.75

1 19/25 = 1.76.

When we divide 19 by 25, we get 0.76.

Then we subtract the decimals.

We should start right and end left.

5 - 6 = -1, we need to borrow one from the closest digit to the left, which is 7. Now we have 15 - 6 = 9.

Next, we have 6 - 7 = -1, we need to borrow one from the closest digit to the left, which is 2. Now we have 16 - 7 = 9.

Our answer right now is 0.99.

Lastly, 1 - 1 = 0.

Which leaves us with the answer: 0.99 (Zero and Ninety Nine Hundredths.)

Best of Luck to you.

If you have any questions, feel free to comment below.

5 0

3 years ago

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

3 years ago

A map has a scale of 1:5000000000 .

erastova [34]

Considering the definition of scale, you obtain:

the real length of the road is 500,000 km.
the real area of the farm is 300 hectares.

<h3>Definition of map</h3>

A map is the conventional graphical representation of a portion of the earth or another celestial body that shows the size and position of elements of the landscape according to the selected scale and projection. That is, a map is a representation of a place, at a size smaller than the actual size.

<h3>Definition of scale</h3>

The scale of a cartographic representation, or map scale (m), is the relationship of similarity between the real dimensions of the geographical space represented and those of its image on the map. In general, it is also defined as the ratio of the lengths of a linear element in the plane and its representation on the terrestrial reference surface.

That is, the scale of the map is defined as the proportionality relationship that exists between a distance measured on the ground and its corresponding measurement on the map.

<h3>Real length of the road</h3>

A map has a scale of 1:5000000000. This indicates that 1 unit on the map is equivalent to 5,000,000,000 in reality.

You know that the road on the map is 10 cm or 0.0001 km long (knowing that 1 km= 100,000 cm).

Then you can apply the following rule of three: if by definition of scale 1 km on the map is equivalent to 5,000,000,000 km in reality, 0.0001 km on the map is equivalent to how much distance in reality?

$real length of the road=\frac{0.0001 kmx 5,000,000,000 km }{1 km}$

<u><em>real length of the road= 500,000 km</em></u>

Finally, the real length of the road is 500,000 km.

<h3>Real area of the farm</h3>

You know that the area of a farm of the map is 6 cm square, 0.0006 m sr 0.00000006 hectares (knowing that 1 cm square= 0.0001 m square and 10,000 m square= 1 hectare).

Then you can apply the following rule of three: if by definition of scale 1 hectare on the map is equivalent to 5,000,000,000 hectares in reality, 0.00000006 hectares on the map is equivalent to how much area in reality?

$real area of the farm=\frac{0.00000006 hectaresx 5,000,000,000 hectares }{1 hectare}$

<u><em>real area of the farm= 300 hectares</em></u>

Finally, the real area of the farm is 300 hectares.

<h3>Summary</h3>

In summary, you get:

the real length of the road is 500,000 km.
the real area of the farm is 300 hectares.

Learn more about scale:

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brainly.com/question/27928319

brainly.com/question/11001778

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#SPJ1

7 0

2 years ago

N - 1/8 = 3/8<br> I am no smort and i forgot to study for a test =|

sdas [7]

Answer:

$\boxed{\sf{n=\dfrac{1}{2}=0.5 }}$

Step-by-step explanation:

Isolate the term of n from one side of the equation.

<h3>n-1/8=3/8</h3>

<u>First, add by 1/8 from both sides.</u>

n-1/8+1/8=3/8+1/8

<u>Solve.</u>

<u>Add the numbers from left to right.</u>

3/8+1/8=4/8

<u>Common factor of 4.</u>

4/4=1

8/4=2

<u>Rewrite as a fraction.</u>

=1/2

n=1/2

<u>Divide is another option.</u>

1/2=0.5

n=1/2=0.5

<u>Therefore, the final answer is n=1/2=0.5.</u>

I hope this helps you! Let me know if my answer is wrong or not.

3 0

2 years ago