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Georgia [21]
2 years ago
7

11. A set of weights includes a 5 lb bar and 8 pairs of weight plates. Each pair of plates weighs 10 lbs. If x

Mathematics
1 answer:
Marat540 [252]2 years ago
4 0
X is amount of plates 10lbs and f(x) is the function
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7 + (10 − 4)2 ÷ 4 × 1\8
natta225 [31]
I’m pretty sure the answer is 12

6 0
2 years ago
I will give brainliest!!!!!
STALIN [3.7K]

Answer:

44 because it goes into both of the numbers twice without going over

Step-by-step explanation:

Hope this helps and i am 100% sure it is correct if you are having doubts. Brainliest please

3 0
2 years ago
me. Ford's kitchen is in the shape of a rectangle with a width of 12.25 feet. She is buying a wallpaper border to go on all of h
Furkat [3]

Answer:

The length of Ms. Ford's kitchen is 57.5 feet.

Step-by-step explanation:

1. You have the following information given in the problem above:

- The kitchen is rectangular.

- Ms. Ford wants to buy 5 extra feet of wallpaper border.

- She buys a total of 62.5 feet of wallpaper border.

2. Therefore, to calculate the length of Ms. Ford's kitchen, you only need to substract 62.5 feet and the 5 extra feet of wallpaper border. Therefore, the result is:

62.5ft-5ft=57.5ft


8 0
3 years ago
a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was
Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em>\bar X<em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

            n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

    P(\bar X \leq 29 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 29-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z \leq 1.60) = 0.94520

                                                                    

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0
2 years ago
Jim had $20 to spend at the video rental. He has a late fee of $4.00 and it will cost him $2.99 to rent each movie. Not includin
hammer [34]

Answer:

he pays the late fee that gives him 16 dollers it cost 3 dollers for  1 video 16 divided by 3 equals 5 so 5 movies with 1 extra doller

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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