Expanding the limit, we get (x^2+2x∆x+∆x^2-2x-2∆x+1-x^2+2x-1)/<span>∆x
Crossing the 1s , the 2xs, and the x^2s out, we get
(2x</span>∆x+∆x^2-2∆x)/<span>∆x
Dividing the </span><span>∆x, we get
2x+</span><span>∆x-2.
Making the limit of </span><span>∆x=0, we get 2x-2.</span>
X is equal to 2 because thirty divide fifteen is two
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Answer:
2
Step-by-step explanation:
The curve's highest value is -1.
The curve's lowest value is -5.
For a symmetrical wave like this*, the amplitude is half the difference between the highest and lowest values:
1/2(-1 -(-5)) = 2
The amplitude is 2.
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* There is no general agreement as to how to compute the amplitude when the wave is asymmetrical. Some authors use the same formula. Some consider the amplitude to be the maximum deviation from average. Some define only a "peak-to-peak" amplitude in those cases. The meaning of "amplitude" in those cases depends on the context in which the question is asked.
Answer:
The GCF for the variable part is ab².
GCF<em>Variable</em>=ab²
Multiply the GCF of the numerical part 5 and the GCF of the variable part ab².
5ab²
Step-by-step explanation:
